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October 6th, 2018, 04:46 PM  #1 
Newbie Joined: Oct 2018 From: Arizona Posts: 1 Thanks: 0  Solution to PvNP
Wondering if a solution to PvNP exists. playing around with it myself. one bit can be a 0 or a 1. if a bit represents the problem of PvNP, and a bit is a variable. then there are 0 or 1 solutions to PvNP. does this sound right? 
October 6th, 2018, 04:57 PM  #2 
Senior Member Joined: Feb 2016 From: Australia Posts: 1,790 Thanks: 629 Math Focus: Yet to find out. 
I think that's it!

October 6th, 2018, 08:38 PM  #3 
Senior Member Joined: Sep 2016 From: USA Posts: 599 Thanks: 366 Math Focus: Dynamical systems, analytic function theory, numerics 
To piggyback on Joppy's astute analysis, just set $P = NP$ and assume we are in a field of characteristic 0. Then we have $P(1N) = 0$ so either $P =0$ or $N = 1$. Just as predicted.

October 6th, 2018, 10:37 PM  #4 
Senior Member Joined: Oct 2009 Posts: 771 Thanks: 278  I'm stealing this solution. I'll publish it and the million dollars is mine. Muaahahahaha


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