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 October 6th, 2018, 04:46 PM #1 Newbie   Joined: Oct 2018 From: Arizona Posts: 1 Thanks: 0 Solution to PvNP Wondering if a solution to PvNP exists. playing around with it myself. one bit can be a 0 or a 1. if a bit represents the problem of PvNP, and a bit is a variable. then there are 0 or 1 solutions to PvNP. does this sound right?
 October 6th, 2018, 04:57 PM #2 Senior Member   Joined: Feb 2016 From: Australia Posts: 1,790 Thanks: 629 Math Focus: Yet to find out. I think that's it! Thanks from SDK
 October 6th, 2018, 08:38 PM #3 Senior Member   Joined: Sep 2016 From: USA Posts: 599 Thanks: 366 Math Focus: Dynamical systems, analytic function theory, numerics To piggyback on Joppy's astute analysis, just set $P = NP$ and assume we are in a field of characteristic 0. Then we have $P(1-N) = 0$ so either $P =0$ or $N = 1$. Just as predicted. Thanks from Maschke
October 6th, 2018, 10:37 PM   #4
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Quote:
 Originally Posted by Sneezly Wondering if a solution to PvNP exists. playing around with it myself. one bit can be a 0 or a 1. if a bit represents the problem of PvNP, and a bit is a variable. then there are 0 or 1 solutions to PvNP. does this sound right?
I'm stealing this solution. I'll publish it and the million dollars is mine. Muaahahahaha

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