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January 26th, 2018, 08:30 AM   #1
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From: leskovac

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proportion of angles 2018

load the attachment
https://www.geogebra.org/m/KrYWuNEv
see the description of the construction
slider - $\displaystyle \alpha$ -select the angle
slider - point P - ruler with a socket, point Q must be line n
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January 27th, 2018, 11:41 PM   #2
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Whether you are from the previous understand how it works proportions of angles, or that you explain step by step?
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January 28th, 2018, 09:50 AM   #3
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What is your "point"?
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February 7th, 2018, 07:22 AM   #4
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DENIS - the solution of the tricection of the angle

Attachments
https://www.geogebra.org/m/HQm7WwFk

on the ruler $AB\infty{_1}\infty{_2}$ , raises divider ADC where AB + AB = AC, ruler sets the angle $\alpha$
semi-line ruler $B\infty{_1}$ sliding on point E , the point A of ruler slides semi-line l , when point C is on the line n , we get the radius of the circle , we get the angle $\beta$
we have solved the tricection of any angle

Look at the construction protocol , or find the error if there is ....
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February 7th, 2018, 11:34 AM   #5
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po_nt = point blank !
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February 12th, 2018, 07:37 AM   #6
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https://www.geogebra.org/m/CukhmEVy

straightedge slip on the point B - line i

divider FIG , slides on straightedge , after slipping point F straighte line BC , point G describes lokus1

section lokus1 and line k point J , when changing the angle, the point J must be manually set to the intersection

construction of regular polygon is possible by means of the proportion of the angle
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April 13th, 2018, 03:21 AM   #7
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Quote:
Originally Posted by point View Post
DENIS - the solution of the tricection of the angle

Attachments
https://www.geogebra.org/m/HQm7WwFk

on the ruler $AB\infty{_1}\infty{_2}$ , raises divider ADC where AB + AB = AC, ruler sets the angle $\alpha$
semi-line ruler $B\infty{_1}$ sliding on point E , the point A of ruler slides semi-line l , when point C is on the line n , we get the radius of the circle , we get the angle $\beta$
we have solved the tricection of any angle

Look at the construction protocol , or find the error if there is ....
Even if this has no error it is just another of the many ways of trisecting an angle using a sliding straight edge- and no one has ever said that was not possible.
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