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November 28th, 2017, 04:10 PM   #1
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Question about my image dealing with domain

Z -> R where f(x) = x^2

Domain is Z
Codomain is R

Image i'm not entirely sure about,

I got {0,1,4,9...}

Am i correct to say this?

Last edited by greg1313; November 28th, 2017 at 05:35 PM.
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November 28th, 2017, 04:17 PM   #2
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domain is $\mathbb{Z}$

codomain is $\mathbb{R}$

range is $\{0\}\cup \{n^2: ~ n\in \mathbb{N}\}$
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November 28th, 2017, 04:27 PM   #3
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Quote:
Originally Posted by romsek View Post
domain is $\mathbb{Z}$

codomain is $\mathbb{R}$

range is $\{0\}\cup \{n^2: ~ n\in \mathbb{N}\}$
So is my image the same as your range?
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November 28th, 2017, 04:32 PM   #4
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the range is the image of the entire domain
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November 28th, 2017, 04:41 PM   #5
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Quote:
Originally Posted by romsek View Post
the range is the image of the entire domain
If z is domain, that includes ...-3,-2,-1,0,1,2,3....

How can the image be the entire domain?

Dont understand what you mean.
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November 28th, 2017, 05:30 PM   #6
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Quote:
Originally Posted by sita View Post
Delete
Image OF the entire domain.

put the whole domain through the function, everything that comes out is the range. This may or may not be the co-domain. In this case it's just a subset of the co-domain.
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