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 November 24th, 2017, 05:28 AM #1 Newbie   Joined: Nov 2017 From: Portugal Posts: 1 Thanks: 0 Use 0 in rule of 3? Hello! I'm doing a AHK script. If 0 does nothing, 1 doubles, what do I do with this: (16/9)/0=(14/9)/x? The number 0 in rule of three screws it all. I just want to have 0 as a normal number. I tried changing 0 to 1 and then subtract 1 from x. It gave me -0,125. I don't know if it worked or if it's even correct, so what can I do?
 November 24th, 2017, 06:44 AM #2 Math Team   Joined: Dec 2013 From: Colombia Posts: 7,675 Thanks: 2655 Math Focus: Mainly analysis and algebra You can't divide by zero.
 December 1st, 2017, 12:11 PM #3 Math Team   Joined: Jan 2015 From: Alabama Posts: 3,264 Thanks: 902 I haven't seen the term "rule of three" in years- and then in a very old book! The "rule of three" is an old term for a proportion- given any three of a, b, c, or d in $\displaystyle a:b::c:d$ or (in more modern notation) $\displaystyle \frac{a}{b}= \frac{c}{d}$, you can solve for the fourth. $\displaystyle \frac{a}{b}= \frac{c}{d}$ can also be written as $\displaystyle \frac{b}{a}= \frac{d}{c}$, $\displaystyle \frac{a}{c}= \frac{b}{d}$ or even $\displaystyle ad= bc$. As others have said, you cannot divide by 0 so it makes no sense to write "$\displaystyle \frac{16/9}{0}= \frac{14/9}{x}$" but that can be written as $\displaystyle \frac{0}{16/9}= \frac{x}{14/9}$ which reduces very quickly to x= 0. In fact, in order for "$\displaystyle \frac{A}{0}= \frac{B}{x}$" to make sense, for any A, B, we must have x= 0.

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