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November 22nd, 2017, 01:58 AM   #1
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A stupid Pyramid

Hey folks, I'm hoping you can help me figure something out.
I got myself someone who wants an aquarium built in the shape of pyramid.
They want the pyramid to fill up 33 percent of the total volume of the room.

Now I figured out that 33 percent of the volume of the room is 942,48 m3
However, what I don't know is how to calculate then the length, breadth, height of the pyramid. Is it possible to get a pyramid from a requested amount of volume? I'm guessing I have to go for best fit?
Can you help with an equation or something?
Yours Truly
The guy stuck with a giant pyramid problem.

I should add that the pyramid should have a square base.

Update - Ok I realised that I can already know the height based on my room size, maybe this makes it easier.
Room height is 11m.

Last edited by skipjack; November 22nd, 2017 at 02:19 PM.
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November 22nd, 2017, 03:33 AM   #2
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Ok, I'm starting to think it's impossible.

Room dimensions are

14×7
height 12 meters

If a pyramid should take up 33 percent of that room, is it even physically possible?

Last edited by skipjack; November 22nd, 2017 at 02:20 PM.
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November 22nd, 2017, 04:06 AM   #3
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Volume of a pyramid is $$\frac13(\text{base area})\times(\text{height})$$
The volume of a rectanular room is $$(\text{base area})\times(\text{height})$$
So they are asking for the pyramid to cover the whole floor and to reach the ceiling.

I think someone is pulling your plonker.

Last edited by skipjack; November 22nd, 2017 at 02:21 PM.
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November 22nd, 2017, 06:16 AM   #4
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I don't know if someone has actually asked you to do this or not but this is over 800 tons of water.

Let's hope it's on the ground floor.
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November 22nd, 2017, 02:27 PM   #5
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Quote:
Originally Posted by Samius229 View Post
I figured out that 33 percent of the volume of the room is 942,48 m3
That's way out. However, the task is impossible if the pyramid's base is square, as distinct from rectangular.
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