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October 26th, 2017, 05:11 AM   #1
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Unhappy Help with this competition math problem.

For every positive integer n, let s(n) denote the number of terminal zeros in the decimal representation of n!. For example, 10! = 3,628,800 ends in two zeros, so s(10) = 2. How many positive integers less than or equal to 2016 cannot be expressed in the form n + s(n) for some positive integer n?

Last edited by skipjack; October 26th, 2017 at 05:48 AM.
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October 26th, 2017, 05:52 AM   #2
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Does this help?
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October 26th, 2017, 06:12 AM   #3
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Originally Posted by skipjack View Post
Does this help?
thank you!
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