
Math General Math Forum  For general math related discussion and news 
 LinkBack  Thread Tools  Display Modes 
September 10th, 2017, 06:40 PM  #1 
Newbie Joined: Jul 2014 From: Taiwan Posts: 8 Thanks: 0  Riemann Hypothesis
P: ζ(sᵢ)=0 Q: sᵢ=σ+it R: t≠0 S: σ=1/2 A: P≡[Q≡(R≡S)] It is that ζ(1/2)=0 if the Proposition A doesn't hold, but actually, ζ(1/2)≈1.4603545; therefore RH does hold. 
September 11th, 2017, 06:38 PM  #2 
Global Moderator Joined: May 2007 Posts: 6,379 Thanks: 542 
I am not sure what you are trying to say. However (using your notation) the Riemann hypothesis states that all zeroes for 0<σ<1 are on the line σ=1/2+it, not necessarily for t=0.

October 20th, 2017, 11:44 AM  #3 
Math Team Joined: Jan 2015 From: Alabama Posts: 2,824 Thanks: 752 
I presume you mean "for 0< σ<1".

October 20th, 2017, 02:13 PM  #4 
Global Moderator Joined: May 2007 Posts: 6,379 Thanks: 542  

Tags 
hypothesis, riemann 
Thread Tools  
Display Modes  

Similar Threads  
Thread  Thread Starter  Forum  Replies  Last Post 
Riemann hypothesis  Tkipp  Number Theory  1  July 8th, 2017 06:08 PM 
Riemann Hypothesis.  mathbalarka  Number Theory  0  October 31st, 2013 01:54 AM 
Do you believe the Riemann hypothesis?  Eureka  Number Theory  1  September 12th, 2011 02:07 PM 
The Riemann Hypothesis and what it say  MyNameIsVu  Complex Analysis  2  April 16th, 2009 08:51 AM 
Riemann Hypothesis  Whoever  Number Theory  72  February 11th, 2009 07:03 AM 