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September 10th, 2017, 05:40 PM   #1
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Riemann Hypothesis

P: ζ(sᵢ)=0
Q: sᵢ=σ+it
R: t≠0
S: σ=1/2

A: P≡[Q≡(R≡S)]

It is that ζ(1/2)=0 if the Proposition A doesn't hold, but actually, ζ(1/2)≈-1.4603545; therefore RH does hold.
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September 11th, 2017, 05:38 PM   #2
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I am not sure what you are trying to say. However (using your notation) the Riemann hypothesis states that all zeroes for 0<σ<1 are on the line σ=1/2+it, not necessarily for t=0.
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