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 May 30th, 2017, 05:27 AM #1 Newbie   Joined: May 2017 From: Lurgan Posts: 1 Thanks: 0 2x2 If two people who were born 6000 years ago, as in the Adam and Eve story and had two children and each two parents after that had two children and no one ever died..... how many people would be in the world today?.ie....2X2 =4...4x2=8....8x2=16...16x2=32 and so on 6000 times (years since creation) Thanks
 May 30th, 2017, 09:04 AM #2 Senior Member   Joined: May 2016 From: USA Posts: 1,310 Thanks: 551 Those are rather peculiar assumptions, but the math is straightforward: $y = 2^{6000} \implies \log_{10}(y) = 6000 * \log_{10}(2) \approx 1806 \implies$ $y = 10^{1806}.$ That is a rather large number: 1 followed by 1806 0's. Last edited by skipjack; May 30th, 2017 at 10:52 AM.
May 30th, 2017, 10:56 AM   #3
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Quote:
 Originally Posted by tomecrawford . . . 6000 times
So each child becomes a parent almost immediately after being born?

May 30th, 2017, 02:12 PM   #4
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Quote:
 Originally Posted by skipjack So each child becomes a parent almost immediately after being born?
I think there is a one year waiting period. It does mean that parents have to tolerate their children's adolescence for a blessedly short duration.

Notice as well that each pair of children in each generation contains one of each sex. Providential I'd venture.

As I pointed out, the assumptions made are odd, but I am guessing that they apply only in pre-apple conditions. Notice that the Garden is quite commodious (as it must be to hold that number of folks).

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