
Math General Math Forum  For general math related discussion and news 
 LinkBack  Thread Tools  Display Modes 
February 11th, 2017, 01:46 PM  #1 
Senior Member Joined: Jan 2013 From: Italy Posts: 154 Thanks: 7  Permutation $(132)(45)$ as a product of transpositions.
Hi, I have this permutation, expressed as product of transpositions: $\sigma = (132)(45) = (12)(13)(45) = (31)(32)(45)(12)(12)$ I understand that $(132)(45) = (12)(13)(45)$, is obtained keeping locked the $1$ in the first cycle and pairing it first with $2$ at the third position, and then with $3$ in the second position. Then, leaving intact $(45)$ since it is already a cycle of two elements. but, how to obtain $(31)(32)(45)(12)(12)$? Can you help me? Thanks! 

Tags 
$13245$, permutation, product, transpositions 
Thread Tools  
Display Modes  

Similar Threads  
Thread  Thread Starter  Forum  Replies  Last Post 
Having trouble with formulas (Equations & Transpositions)  jayinwww  Algebra  2  November 8th, 2016 12:38 AM 
Permutation being written as product of cycles.  MadSoulz  Abstract Algebra  6  February 11th, 2015 08:24 AM 
transpositions of a set  terms and notations  zFADwww7  Advanced Statistics  0  November 14th, 2013 04:25 AM 
Proof on product of cycles (permutation groups)  Kappie  Abstract Algebra  1  March 13th, 2012 09:30 PM 
permutation as a product of factors  Frazier001  Abstract Algebra  1  October 23rd, 2007 12:22 AM 