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 February 2nd, 2017, 08:38 PM #1 Member   Joined: Oct 2016 From: labenon Posts: 33 Thanks: 4 Perfect Numbers I was searching some mathematical formulas and come across this question. Can any one help me to solve this.? I studied that a perfect number is one which equals the sum of its proper divisors. For example: the number 18 is abundant since 18 is less than 1 + 2 +3 + 6 + 9 =21, the number 15 is deficient since 15 is greater than 1+3+5 =9 and 6 =1+ 2 + 3 is perfect. Then I found the equation to find perfect even numbers : m = 2^(p-1) * (2^p - 1) , where p is prime number. Now the main question is from this equation : Can we find how many even & odd perfect numbers are there? February 2nd, 2017, 08:46 PM #2 Senior Member   Joined: Aug 2012 Posts: 2,191 Thanks: 643 It's an open question as to whether any odd perfect numbers exist. This is a famous problem in math. Here's an article about it. They've checked up to $10^{300}$ and not found any. That's $1$ with $300$ zeros. But compared to all the natural numbers that there are, it's just a drop in the bucket. Odd Perfect Numbers: Do They Exist? Thanks from AshBox February 3rd, 2017, 03:53 AM #3 Newbie   Joined: Dec 2016 From: United Kingdom Posts: 14 Thanks: 1 I think this is still debatable questions, still I have found one article which can help you to solve this: Odd Perfect Number -- from Wolfram MathWorld February 4th, 2017, 02:06 PM   #4
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 Originally Posted by SophiaRivera007 I think this is still debatable questions, still I have found one article which can help you to solve this: Odd Perfect Number -- from Wolfram MathWorld
Hey My Math Forum members and guests!

Did you see the credit given at the bottom of this wolfram link for contributing information? Our very own CRGreathouse!!!

What a wonderful surprise and delight  February 5th, 2017, 01:47 PM   #5
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Quote:
 Originally Posted by AshBox I was searching some mathematical formulas and come across this question. Can any one help me to solve this.? I studied that a perfect number is one which equals the sum of its proper divisors. For example: the number 18 is abundant since 18 is less than 1 + 2 +3 + 6 + 9 =21, the number 15 is deficient since 15 is greater than 1+3+5 =9 and 6 =1+ 2 + 3 is perfect. Then I found the equation to find perfect even numbers : m = 2^(p-1) * (2^p - 1) , where p is prime number. Now the main question is from this equation : Can we find how many even & odd perfect numbers are there?
Does the equation (m=....) generate all even perfect numbers? February 5th, 2017, 02:28 PM #6 Global Moderator   Joined: Dec 2006 Posts: 20,370 Thanks: 2007 Yes. Note that 2^p - 1 needs to be prime as well for m to be a perfect number. It's not known whether the number of perfect numbers is finite. February 5th, 2017, 09:33 PM   #7
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Perfect Numbers

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 Originally Posted by mathman Does the equation (m=....) generate all even perfect numbers?
Yes, absolutely this works and provide you perfect numbers. Tags numbers, perfect, prime Thread Tools Show Printable Version Email this Page Display Modes Linear Mode Switch to Hybrid Mode Switch to Threaded Mode Similar Threads Thread Thread Starter Forum Replies Last Post McPogor Number Theory 10 April 10th, 2014 06:52 AM mathbalarka Number Theory 4 September 1st, 2012 02:27 PM Wissam Number Theory 18 July 25th, 2010 12:34 AM momo Number Theory 14 April 27th, 2009 05:18 PM soandos Number Theory 2 November 27th, 2007 04:42 AM

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