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January 4th, 2017, 01:23 AM  #1 
Newbie Joined: Jan 2017 From: Turkey Posts: 1 Thanks: 0  Possible to find at least 1 indefinite value in 5 related procedures?
I have 5 procedures listed below: 1. (x+y+z)/x1=252.81 2. (x+1.5y+z)/x1=292.13 3. (2x+1.5y+z)/x1=449.44 4. (2x+2y+2z)/x1=505.62 5. (3x+2y+2z)/x1=662.92 x, y, z & x1 are variables but used same in each procedures. Considering the related procedures what is the possibility to find at least one of the value assigned to x or y? If not possible from the given data the proximate value of z can be estimated but x, y, & x1 are always unpredictable. The required values in procedures above are: 1. (140+70+15)/0.89=252.81 2. (140+105+15)/0.89=292.13 3. (280+105+15)/0.89=449.44 4. (280+140+30)/0.89=505.62 5. (420+140+30)/0.89=662.92 Thanks in advance. Last edited by zrs; January 4th, 2017 at 01:57 AM. 
January 4th, 2017, 01:19 PM  #2 
Global Moderator Joined: May 2007 Posts: 6,540 Thanks: 591 
Equation 4 is equation 1 times 2, therefore not independent. You have 4 equations in four unknowns.


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