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 January 4th, 2017, 01:23 AM #1 Newbie   Joined: Jan 2017 From: Turkey Posts: 1 Thanks: 0 Possible to find at least 1 indefinite value in 5 related procedures? I have 5 procedures listed below: 1. (x+y+z)/x1=252.81 2. (x+1.5y+z)/x1=292.13 3. (2x+1.5y+z)/x1=449.44 4. (2x+2y+2z)/x1=505.62 5. (3x+2y+2z)/x1=662.92 x, y, z & x1 are variables but used same in each procedures. Considering the related procedures what is the possibility to find at least one of the value assigned to x or y? If not possible from the given data the proximate value of z can be estimated but x, y, & x1 are always unpredictable. The required values in procedures above are: 1. (140+70+15)/0.89=252.81 2. (140+105+15)/0.89=292.13 3. (280+105+15)/0.89=449.44 4. (280+140+30)/0.89=505.62 5. (420+140+30)/0.89=662.92 Thanks in advance. Last edited by zrs; January 4th, 2017 at 01:57 AM. January 4th, 2017, 01:19 PM #2 Global Moderator   Joined: May 2007 Posts: 6,835 Thanks: 733 Equation 4 is equation 1 times 2, therefore not independent. You have 4 equations in four unknowns. Tags equations, find, indefinite, procedures, ratio, related Thread Tools Show Printable Version Email this Page Display Modes Linear Mode Switch to Hybrid Mode Switch to Threaded Mode Similar Threads Thread Thread Starter Forum Replies Last Post aaron-math Calculus 4 October 2nd, 2011 08:23 PM creativewang Calculus 10 July 1st, 2011 12:34 PM -DQ- Calculus 2 June 5th, 2010 04:34 AM aleusha007 Calculus 2 June 27th, 2008 07:15 AM shepherdm1270 Calculus 1 April 14th, 2008 10:51 AM

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