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November 12th, 2016, 09:05 PM   #1
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Question Maths problem!!

I've been trying to solve this for a while and I can't get it right. Please help.

Calculate the ratio of the volumes of two cylinders whose dimensions are in the ratio 5 : 8.

Thanks.

Last edited by skipjack; November 13th, 2016 at 03:01 AM.
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November 12th, 2016, 09:29 PM   #2
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$V = \pi r^2 h$

$\dfrac {V_5}{V_8} = \dfrac{\pi (5r)^2 (5h)}{\pi (8r)^2 (8h)}=\left(\dfrac 5 8 \right)^3=\dfrac{125}{256}$
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November 13th, 2016, 03:21 AM   #3
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If two solids, each with finite, non-zero volume, are geometrically similar, with a scale ratio of a:b, their volumes are in the ratio a³:b³.
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December 20th, 2016, 09:56 PM   #4
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Question Maths problem!

Hi, You can use this simple formula: V = hπr^2.

I am not an expert. So I Generally find online calculation tools, like Math-Calculator, AshBox etc. If you want to find quick answers.
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December 21st, 2016, 08:28 AM   #5
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But what if you want to learn? I would hope that was why most people came here!
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