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March 26th, 2016, 11:31 PM  #1 
Newbie Joined: Mar 2016 From: FL, USA Posts: 1 Thanks: 0  solving equation with log
Let's say we have an equation: RES = log(PER + 1)/log(2) how can I solve this equation for PER with different values of RES, say 10 or 16? Thanks. Last edited by skipjack; March 27th, 2016 at 12:37 AM. 
March 27th, 2016, 12:08 AM  #2 
Senior Member Joined: Feb 2016 From: Australia Posts: 1,600 Thanks: 546 Math Focus: Yet to find out. 
There is an easy solution if your logs are base e. Are they?

March 27th, 2016, 12:35 AM  #3 
Global Moderator Joined: Dec 2006 Posts: 19,174 Thanks: 1644 
${\small\text{PER}} = 2^{\text{RES}}  1$

March 27th, 2016, 08:18 AM  #4 
Math Team Joined: Oct 2011 From: Ottawa Ontario, Canada Posts: 12,758 Thanks: 860 
Tattoo this on your wrist: if a^p = x then p = log(x) / log(a) 
April 6th, 2016, 08:15 AM  #5  
Math Team Joined: Jan 2015 From: Alabama Posts: 3,240 Thanks: 885  Quote:
$\displaystyle a^{RES log(2)}= (a^{log(2))^{RES}= a^{log(PER+ 1)}$ $\displaystyle 2^{RES}= PER+ 1$ $\displaystyle PER= 2^{RES} 1$ Notice that this answer does not involve "a" so it does not matter what to what base the logarithm is.  

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equation, log, solving 
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