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February 3rd, 2016, 10:11 AM  #11 
Newbie Joined: Feb 2016 From: England Posts: 8 Thanks: 0 
Thank you skipjack. That all does make sense now. So if I want to know the largest allowable L to ctr of gravity for a tool of known weight (W) I have (31.4/9.8)/W(Kg) = L(m) So maximum weight tool of 20Kg would give me a maximum length L to ctr of gravity of 160.2mm. That sounds feasible. Thank you very much for your time and assistance. Very much appreciated sir. Last edited by skipjack; February 3rd, 2016 at 10:14 AM. 

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