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February 3rd, 2016, 10:11 AM   #11
Joined: Feb 2016
From: England

Posts: 8
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Thank you skipjack.
That all does make sense now.

So if I want to know the largest allowable L to ctr of gravity for a tool of known weight (W)
I have
(31.4/9.8)/W(Kg) = L(m)

So maximum weight tool of 20Kg would give me a maximum length L to ctr of gravity of 160.2mm. That sounds feasible.

Thank you very much for your time and assistance. Very much appreciated sir.

Last edited by skipjack; February 3rd, 2016 at 10:14 AM.
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