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November 17th, 2015, 03:49 PM | #1 |
Member Joined: Nov 2015 From: New York State Posts: 41 Thanks: 0 | Energy and mass
E=mc^2 E/m = c^2 what is the ratio of Energy to mass in the Universe? |
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November 17th, 2015, 04:56 PM | #2 |
Global Moderator Joined: May 2007 Posts: 6,685 Thanks: 661 |
Total energy in the universe is an open question. There is a zero energy model, where gravity is the negative part. There are also concepts, dark matter and dark energy which add further difficulties to getting an answer.
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November 17th, 2015, 05:53 PM | #3 |
Member Joined: Nov 2015 From: New York State Posts: 41 Thanks: 0 |
From this, it seems that value of Energy or mass can not be infinite.
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November 17th, 2015, 08:40 PM | #4 | |
Math Team Joined: May 2013 From: The Astral plane Posts: 2,042 Thanks: 815 Math Focus: Wibbly wobbly timey-wimey stuff. | Quote:
-Dan | |
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November 18th, 2015, 03:28 PM | #5 |
Member Joined: Nov 2015 From: New York State Posts: 41 Thanks: 0 |
E=mc^2 E/m=c^2 Maximum_Energy / 1 = c^2 We know the mass (1), we know what value c^2 has, we can solve for Maximum_Energy. 1 / Maximum_mass = c^2 We know Energy (1), we know what value c^2 has, we can solve for Maximum_mass. |
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November 18th, 2015, 03:47 PM | #6 |
Math Team Joined: Dec 2013 From: Colombia Posts: 7,600 Thanks: 2588 Math Focus: Mainly analysis and algebra |
You do know that the E and m in that equation are changes in quantities, right? So in fission, the energy released E is equal to the speed of light multiplied by the difference between the total mass of uranium before the fission event and the total mass of all the elements left after the fission event.
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November 18th, 2015, 04:20 PM | #7 |
Member Joined: Nov 2015 From: New York State Posts: 41 Thanks: 0 |
I have not looked at nuclear fission much. I did look at nuclear fusion and it can be a cycle. The CNO cycle (for carbon–nitrogen–oxygen) is one of the two (known) sets of fusion reactions by which stars convert hydrogen to helium, the other being the proton–proton chain reaction. I'm not sure how fission comes into play with E=mc^2. My question was: Can you solve for Maximum_Energy and/or Maximum_mass knowing c^2? |
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November 18th, 2015, 05:30 PM | #8 |
Math Team Joined: May 2013 From: The Astral plane Posts: 2,042 Thanks: 815 Math Focus: Wibbly wobbly timey-wimey stuff. | |
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November 18th, 2015, 07:21 PM | #9 |
Member Joined: Nov 2015 From: New York State Posts: 41 Thanks: 0 |
E/m=c^2 Maximum_Energy / 1 = c^2 Maximum_Energy / 1 = 8.98755179*10^16 / 1 8.98755179*10^16 * 1 = Maximum_Energy * 1 Maximum_Energy = 8.98755179*10^16 I hope I cross multiplied correctly. Same can be done if you substitute 1 for Maximum_mass and solve. Here c^2 = 8.98755179*10^16 The reason why I called it Maximum_Energy is because if mass is set to 1, it is at its minimum (and Energy should be at its maximum) Right? I guess mass could be set to be even smaller, for example instead of 1, it could be set at 0.5?, but then the math gets more complicated. Last edited by Alamar; November 18th, 2015 at 07:26 PM. |
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November 18th, 2015, 09:29 PM | #10 | |
Math Team Joined: May 2013 From: The Astral plane Posts: 2,042 Thanks: 815 Math Focus: Wibbly wobbly timey-wimey stuff. | Quote:
We really need a better clue as to what you are talking about before we can give you a decent answer. -Dan | |
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