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 February 3rd, 2012, 06:00 PM #1 Joined: Nov 2011 Posts: 10 Thanks: 0 Limit matlab answer I want to take the limit of log(-(5^(1/2)*((-347922205179541/562949953421312)^n - (910872158600853/562949953421312)^n as n tends to infinity, but the answer in matlab always return the the whole thing,can anyone tell me how to get the exact answer? The command i put in was limit(log(-(5^(1/2)*((-347922205179541/562949953421312)^n - (910872158600853/562949953421312)^n))/5)/n,Inf) And the answer i got from matlab was ans = limit(log(-(5^(1/2)*((-347922205179541/562949953421312)^n - (910872158600853/562949953421312)^n))/5)/n, n = Inf)
 February 3rd, 2012, 08:13 PM #2 Global Moderator     Joined: Nov 2006 From: UTC -5 Posts: 14,011 Thanks: 427 Math Focus: Number theory, computational mathematics, combinatorics, FOM, symbolic logic Re: Limit matlab answer Your first formula doesn't have matching parentheses, so I don't know what it's supposed to mean. Generally, it looks like you're basically taking the limit of log(a^n - b^n) with a few extra frills going on. This will be the same as the limit of log(a^n) as long as a > b, since the other factor will add at most a hyperbolic correction factor. Of course this can be simplified to n log a.
 February 4th, 2012, 07:39 AM #3 Joined: Nov 2011 Posts: 10 Thanks: 0 Re: Limit matlab answer I understand what you mean, but can you tell me how to get an exact answer, like ans=2134 or something?
 February 4th, 2012, 06:10 PM #4 Global Moderator     Joined: Nov 2006 From: UTC -5 Posts: 14,011 Thanks: 427 Math Focus: Number theory, computational mathematics, combinatorics, FOM, symbolic logic Re: Limit matlab answer I don't remember MatLab well enough to do that, sorry. It's been years since I last used it, and I wasn't even all that good then.
 February 13th, 2012, 12:25 AM #5 Joined: Feb 2012 Posts: 2 Thanks: 0 Re: Limit matlab answer Perhaps, you have compiled the matlab software incorrectly. http://www.topckit.com

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