My Math Forum Math Q&A challenge (Part 11)

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 August 23rd, 2013, 06:06 AM #1 Math Team   Joined: Oct 2011 From: Ottawa Ontario, Canada Posts: 14,597 Thanks: 1038 Math Q&A challenge (Part 11) You have an integer number where any digit appears at most twice. The sum of all neighboring four digits in this number is a square. Example: 205290 is such a number because no digit appears more than twice, and 2+0+5+2, 0+5+2+9, and 5+2+9+0 are squares. What is the maximum possible value for this number?
 August 24th, 2013, 02:34 PM #2 Math Team     Joined: Jul 2011 From: North America, 42nd parallel Posts: 3,372 Thanks: 233 Re: Math Q&A challenge (Part 11) This is interesting , I'll make the frst submission. How about 9880013571357 ?
 August 24th, 2013, 07:03 PM #3 Math Team   Joined: Oct 2011 From: Ottawa Ontario, Canada Posts: 14,597 Thanks: 1038 Re: Math Q&A challenge (Part 11) Good try Agent...there is a higher number.
August 24th, 2013, 07:37 PM   #4
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Re: Math Q&A challenge (Part 11)

Quote:
 Originally Posted by Denis Good try Agent...there is a higher number.

 August 24th, 2013, 08:09 PM #5 Math Team     Joined: Jul 2011 From: North America, 42nd parallel Posts: 3,372 Thanks: 233 Re: Math Q&A challenge (Part 11)
 August 24th, 2013, 08:13 PM #6 Math Team   Joined: Oct 2011 From: Ottawa Ontario, Canada Posts: 14,597 Thanks: 1038 Re: Math Q&A challenge (Part 11) Looked at both links. What do I not see?
 August 24th, 2013, 08:30 PM #7 Math Team     Joined: Jul 2011 From: North America, 42nd parallel Posts: 3,372 Thanks: 233 Re: Math Q&A challenge (Part 11) CRG gave me a 'ribbing' using Mario so I countered with Wario... you have to know about video game plumbers ... and bizzarro characters of a stienfool universe ... Don't worry, you didn't miss anything important. I tried a few more but can't get a bigger number.
 August 24th, 2013, 10:17 PM #8 Global Moderator   Joined: Dec 2006 Posts: 20,972 Thanks: 2222 81978100367936
August 24th, 2013, 10:23 PM   #9
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Re: Math Q&A challenge (Part 11)

Quote:
 Originally Posted by skipjack 81978100367936
That's what I get. I believe it's optimal, though I would wait for Denis's approval.

By the way, skipjack, if you don't have any question to ask then just pass it to someone for the game to continue, ok?

 August 24th, 2013, 10:44 PM #10 Senior Member   Joined: Sep 2012 From: British Columbia, Canada Posts: 764 Thanks: 53 Re: Math Q&A challenge (Part 11) And it looks like we forgot to post the rules AGAIN. :P

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