August 24th, 2013, 11:16 PM  #11 
Global Moderator Joined: Dec 2006 Posts: 18,034 Thanks: 1393 
If it's correct, I ask for one word (various possible) that will indicate that you have solved the problem already posted here. The only reason for not yet posting the solution itself is that I can't be sure the problem isn't from a current competition that's still open.

August 24th, 2013, 11:57 PM  #12  
Math Team Joined: Oct 2011 From: Ottawa Ontario, Canada Posts: 10,653 Thanks: 697  Re: Quote:
7 pairs, no 2,4,5 ; surprising...  
August 25th, 2013, 05:27 AM  #13 
Global Moderator Joined: Dec 2006 Posts: 18,034 Thanks: 1393 
The number problem seems to be an original problem from the puzzleup web site. The site doesn't give solutions, but apparently retains puzzles even when they've been solved elsewhere.

August 25th, 2013, 07:06 AM  #14  
Global Moderator Joined: Nov 2006 From: UTC 5 Posts: 16,046 Thanks: 937 Math Focus: Number theory, computational mathematics, combinatorics, FOM, symbolic logic, TCS, algorithms  Re: Math Q&A challenge (Part 11) Quote:
 
August 25th, 2013, 09:09 AM  #15  
Math Team Joined: Oct 2011 From: Ottawa Ontario, Canada Posts: 10,653 Thanks: 697  Re: Quote:
that you have solved the problem already posted here." You're confusing me, Skip. The link you provide leads to a problem elsewhere at this site, called "Dividing a parallelogram": what's that got to do with my puzzle/problem? What does "one word (various possible)" mean? And YES, my puzzle is one I saw at Puzzleup...and recently... BUT how can I be "fishing" for an answer if I already have a solution? OR how would I have been able to tell Secret Agent Man(!) his solution was not the maximum number? Or is there a rule that states that the puzzles we post here MUST be invented by ourselves? Or should I have stated: "found this at another site"?  
August 25th, 2013, 06:30 PM  #16 
Math Team Joined: Jul 2011 From: North America, 42nd parallel Posts: 3,372 Thanks: 233  Re: Math Q&A challenge (Part 11)
C'mon skipper, ask a question or transfer control please. 
August 25th, 2013, 06:44 PM  #17  
Global Moderator Joined: Dec 2006 Posts: 18,034 Thanks: 1393  Quote:
 
August 25th, 2013, 07:07 PM  #18 
Math Team Joined: Oct 2011 From: Ottawa Ontario, Canada Posts: 10,653 Thanks: 697  Re: Math Q&A challenge (Part 11)
Darn it...thought we were done with wrapping cubes in parallelogramic plastic 
August 26th, 2013, 06:29 AM  #19 
Math Team Joined: Jul 2011 From: North America, 42nd parallel Posts: 3,372 Thanks: 233  Re: Math Q&A challenge (Part 11)
I could solve the problem if we start with a 10×15 rectangle, just make 1 cut in the shape of a "Z" with 90° interior angles, then fold. The parallelogram is throwing me off. 
August 26th, 2013, 07:23 AM  #20 
Global Moderator Joined: Dec 2006 Posts: 18,034 Thanks: 1393 
Or one straight cut to divide the rectangle into two 5×15 rectangles.


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