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November 4th, 2010, 04:44 AM  #1 
Newbie Joined: Nov 2010 Posts: 3 Thanks: 0  A conjecture you might be very interested!
Assume Q is a convex central symmetric curve, whose area is S. The area of the maximum parallelogram inside Q is S'. How to prove that S'/S >= 2/pi? For example, If Q is an ellipse, S'=2ab, S=pi*ab. If Q is a regular hexagon, S'/S=2/3. 

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