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 September 21st, 2014, 05:58 AM #1 Newbie   Joined: Sep 2014 From: Toronto Posts: 7 Thanks: 0 Systems of 3 Linear Equations- solutions i need help with this question, thanx all question: Consider the system of linear equations: x+y+z=6 3x+2y+z=10 mx+2y+z=n For what values of m and n does the system of equations have: 1) no solutions? 2) a unique solution? 3) infinitely many solutions? September 21st, 2014, 08:34 AM #2 Math Team   Joined: Dec 2013 From: Colombia Posts: 7,674 Thanks: 2654 Math Focus: Mainly analysis and algebra Equation 3 less equation 2 $$(m-3)x = n-10$$ So $m \ne 3$ has at one solution for $x$ (you need to check that you get unique solutions for $y$ and $z$). $m = 3, n=10$ implies that any value of $x$ will work. Again this can be verified (and fine tuned) in the system. $m=3, n \ne 10$ has no solutions. Last edited by v8archie; September 21st, 2014 at 08:42 AM. September 21st, 2014, 08:34 AM   #3
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Quote:
 Originally Posted by Sadia x+y+z=6 3x+2y+z=10 mx+2y+z=n
Math help sites can't conduct classrooms...

Can you solve this system for x, y and z?

x+y+z=6
3x+2y+z=10
5x+2y+z=12

Show us what you can do... September 21st, 2014, 08:55 AM   #4
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 Originally Posted by Denis Math help sites can't conduct classrooms... Can you solve this system for x, y and z? x+y+z=6 3x+2y+z=10 5x+2y+z=12 Show us what you can do...
-Substitution method-
solve x+y+z=6 for z:
Z=6-x-y
substitute into the other two equations:
so, 3x+2y+z=10; 2x+y=4
and, 5x+2y+z=12; 4x+y=6
solve by eliminating y out of the above two equations:
x=1
then by substituting x into 2x+y=4, you get y= 2, then by substituting both x and y into z=6-x-y you get the value of z which is 3.

so: x=1, y=2 and z=3

i know how to do the basics but its hard for a 10th grader to these kind of questions when ur teacher doesnt explain how to do it  September 21st, 2014, 10:31 AM   #5
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 Originally Posted by Sadia i know how to do the basics but its hard for a 10th grader to these kind of questions when ur teacher doesnt explain how to do it GOOD work!
Please use proper English, like ur = your; that's for YOUR benefit.

Did you read Archie's answer? Are you ok now? September 27th, 2014, 03:55 PM   #6
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Quote:
 Originally Posted by Denis GOOD work! Please use proper English, like ur = your; that's for YOUR benefit. Did you read Archie's answer? Are you ok now?
Oh I'm sorry I didn't realize this was a grammar forum..... I'll remember that the next time I go on a MATH forum. And no need to get so mad. I didn't realize saying ur instead of YOUR would mean so much. In the future if you happen to get annoyed with someone's questions just ignore it. This is a math forum, I'm pretty sure that means you come to get help, not to get sour and annoyed remarks from people. You don't want to help? Then mind YOUR own business. September 27th, 2014, 05:18 PM #7 Math Team   Joined: Oct 2011 From: Ottawa Ontario, Canada Posts: 14,597 Thanks: 1038 Well, if that's the way you're taking it, so be it. Good luck. Tags equations, linear, solutions, systems Thread Tools Show Printable Version Email this Page Display Modes Linear Mode Switch to Hybrid Mode Switch to Threaded Mode Similar Threads Thread Thread Starter Forum Replies Last Post kaspis245 Algebra 9 August 8th, 2014 10:07 AM david940 Linear Algebra 2 July 25th, 2014 06:12 PM Akcope Calculus 3 March 14th, 2014 01:49 AM Jake_88 Linear Algebra 1 June 15th, 2010 05:59 AM maxpalme Algebra 1 April 2nd, 2009 10:33 AM

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