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 September 18th, 2014, 08:47 AM #1 Newbie   Joined: Sep 2014 From: Houston Posts: 1 Thanks: 0 Linear Equation Problem Find the equation of the line parallel to the graph of 4x+7y=28 that has an x intercept of 3
 September 18th, 2014, 09:19 AM #2 Math Team   Joined: Dec 2013 From: Colombia Posts: 7,559 Thanks: 2561 Math Focus: Mainly analysis and algebra If one line is parallel to another, they both have the same gradient. Given a point $P(x,y)$ on the line, the gradient shows how the $x$ and $y$ coordinates of $P$ change with respect to each other as the point moves along the line. The easiest way to see this is to write the equation in the form $$y = mx+c$$ when $m$ is the gradient. If we put $x= 0$ into this equation we get $y=c$, so $c$ is the value at which the line intercepts the y-axis (which has the equation $x=0$). To find the intercept with the x-axis, we not that the x-axis has the equation $y=0$. So, we can put $y=0$ in the equation of the line and solve for $x$. Can you have a go at the question now? Thanks from topsquark
September 18th, 2014, 02:07 PM   #3
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Quote:
 Originally Posted by willreyes93 Find the equation of the line parallel to the graph of 4x+7y=28 that has an x intercept of 3
Parallel line is of the form 4x+7y=c. Compute c from the intercept condition.

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