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September 18th, 2014, 07:47 AM   #1
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Linear Equation Problem

Find the equation of the line parallel to the graph of 4x+7y=28 that has an x intercept of 3
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September 18th, 2014, 08:19 AM   #2
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If one line is parallel to another, they both have the same gradient. Given a point $P(x,y)$ on the line, the gradient shows how the $x$ and $y$ coordinates of $P$ change with respect to each other as the point moves along the line. The easiest way to see this is to write the equation in the form $$y = mx+c$$
when $m$ is the gradient. If we put $x= 0$ into this equation we get $y=c$, so $c$ is the value at which the line intercepts the y-axis (which has the equation $x=0$). To find the intercept with the x-axis, we not that the x-axis has the equation $y=0$. So, we can put $y=0$ in the equation of the line and solve for $x$.

Can you have a go at the question now?
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September 18th, 2014, 01:07 PM   #3
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Quote:
Originally Posted by willreyes93 View Post
Find the equation of the line parallel to the graph of 4x+7y=28 that has an x intercept of 3
Parallel line is of the form 4x+7y=c. Compute c from the intercept condition.
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