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 February 28th, 2014, 05:47 PM #1 Senior Member   Joined: Nov 2013 Posts: 137 Thanks: 1 Connection between cesaro equation and polar coordinates First, I'd like that you read this littler article (http://mathworld.wolfram.com/NaturalEquation.html). The solution given by Euler that coonects the system cartesian (x, y) with the curvature ? of the "cesaro system" (s, ?), is that the derivative of the cartesian tangential angle ?* wrt arc length s results the curvature ?. However, in the 2D plane is definied the polar tangential angle ?* too. Thus if I want express a curve given s and ? in terms of r and ? (or vice-versa) I need to establish a connection between the curvature ? and the polar system. So, would be correct to say that the derivative of ? wrt s is equal to ?? * https://en.wikipedia.org/wiki/Tangential_angle https://en.wikipedia.org/wiki/Subtangent https://en.wikipedia.org/wiki/List_o....A0ro_equation EDIT:  Tags cesaro, connection, coordinates, equation, polar Thread Tools Show Printable Version Email this Page Display Modes Linear Mode Switch to Hybrid Mode Switch to Threaded Mode Similar Threads Thread Thread Starter Forum Replies Last Post micle Algebra 1 June 18th, 2013 02:09 PM thescratchy Calculus 0 March 5th, 2011 09:25 PM jj007 Calculus 2 June 15th, 2010 06:52 AM fact93 Calculus 2 February 28th, 2008 06:48 PM Eppo Algebra 5 January 9th, 2008 01:35 PM

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