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 January 19th, 2014, 12:47 PM #1 Newbie   Joined: Jan 2014 Posts: 3 Thanks: 0 Grams determinant Prove that determinant of grams G(x1,…,xn)=0 if x1,…,xk are linearly dependent. Please if someone could solve this for me,because i have no idea how to prove this.
 January 19th, 2014, 12:49 PM #2 Newbie   Joined: Jan 2014 Posts: 3 Thanks: 0 Re: Grams determinant Prove that determinant of Grams matrix is zero, G(x1,…,xn)=0 if x1,…,xk are linearly dependent.
January 19th, 2014, 08:32 PM   #3
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Re: Grams determinant

Quote:
 Originally Posted by Mooky Please if someone could solve this for me,because i have no idea how to prove this.
WHY were you asked to prove it if you have no idea? Sadistic teacher?

January 20th, 2014, 02:22 PM   #4
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Re: Grams determinant

Quote:
Originally Posted by Denis
Quote:
 Originally Posted by Mooky Please if someone could solve this for me,because i have no idea how to prove this.
WHY were you asked to prove it if you have no idea? Sadistic teacher?
Hahah not really,i was sick for some time now,and i'm really triying to catch up.I missed some classes about determinants and inner product spaces.
Now i know i should pick some vector that is linearly dependent,and use the linear property of the inner product and expand the Grams determinant.Now what i dont understand is the "expand" part.

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