January 19th, 2014, 12:47 PM  #1 
Newbie Joined: Jan 2014 Posts: 3 Thanks: 0  Grams determinant
Prove that determinant of grams G(x1,…,xn)=0 if x1,…,xk are linearly dependent. Please if someone could solve this for me,because i have no idea how to prove this. 
January 19th, 2014, 12:49 PM  #2 
Newbie Joined: Jan 2014 Posts: 3 Thanks: 0  Re: Grams determinant
Prove that determinant of Grams matrix is zero, G(x1,…,xn)=0 if x1,…,xk are linearly dependent.

January 19th, 2014, 08:32 PM  #3  
Math Team Joined: Oct 2011 From: Ottawa Ontario, Canada Posts: 14,274 Thanks: 1023  Re: Grams determinant Quote:
 
January 20th, 2014, 02:22 PM  #4  
Newbie Joined: Jan 2014 Posts: 3 Thanks: 0  Re: Grams determinant Quote:
Now i know i should pick some vector that is linearly dependent,and use the linear property of the inner product and expand the Grams determinant.Now what i dont understand is the "expand" part.  

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