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September 19th, 2013, 12:56 PM   #1
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Component Form of Vector Given Magnitude and Angle

The vector in 3-space of length 3 lying in the xz-plane pointing upward at an angle of 150 measured from the positive x-axis.

I know how to find this with a 2D (x,y) but not for 3D(x,y,z)
3(cos150,sin150)
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September 19th, 2013, 01:41 PM   #2
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Re: Component Form of Vector Given Magnitude and Angle

"In the xz plane" means the y component is 0. Apply your formulas to (x, 0, z).
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