- **Linear Algebra**
(*http://mymathforum.com/linear-algebra/*)

- - **Generalized Pythagorean theorem**
(*http://mymathforum.com/linear-algebra/345080-generalized-pythagorean-theorem.html*)

Generalized Pythagorean theoremHi, let S be bounded piece of a plane in the space E3 and let's note Si an orthogonal projection of S into xy, xz and yz planes respectively. Then it can be proved that (1) $\displaystyle area(S)^2=area(S1)^2+area(S2)^2+area(S3)^2$. But there is also a general theorem, that in a vector space with dot product where u,v,w are orthogonal vectors the identity (2) $\displaystyle |u+v+w|^2=|u|^2+|v|^2+|w|^2$ is true. There is great similarity between (1) and (2) here so my question is - can (1) be proved with help of (2), ie can S,Si be somehow interpreted as some vectors of some vector space (such that Si are orthogonal and S=S1+S2+S3)? Thank you for any suggestions. |

Interesting question. Any three vectors can be interpreted as orthogonal components of an area vector A=u+v+w. But that doesn't prove the area projection formula. You have to prove that the projection of an area vector A onto a plane whose normal is n is A.n. Not that easy as I recall, a little subtle. |

Itâ€™s interesting to note that you can project an area vector onto 3 non-orthogonal planes in which case A=u+v+w is still true but A^2=(u+v+w)^2 is u.u+u.v+u.w....... |

All times are GMT -8. The time now is 10:39 AM. |

Copyright © 2019 My Math Forum. All rights reserved.