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March 20th, 2018, 01:28 PM   #1
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linear algebra

Hello everyone,

I am kind of new in the whole linear algebra subject.


My teacher gave me a question that I struggled with.

I was requested to find x from a given equation:

ABC^tx^-1BA^tC=AB^t

Basically, he manipulated the equation in A^tB^-1A^-1 and I didn't understand the whole idea inside the solution,

so I will be really glad if someone can help me with the confusion.

Last edited by skipjack; March 21st, 2018 at 11:29 AM.
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March 20th, 2018, 06:05 PM   #2
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Quote:
Originally Posted by someone111888 View Post
ABC^tx^-1BA^tC=AB^t
Is this your equation:
A * B * C^t * x^(-1) * B * A^t * C = A * B^t
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March 21st, 2018, 08:57 AM   #3
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Well, IF that is your equation, then:

x = [A^t * C^(t+1)] / [B^(t-2)]
Can be "shown" this way:
x = A^t * C^(t+1) * B^(2-t)

Remember that x^(-1) = 1/x

Last edited by Denis; March 21st, 2018 at 09:03 AM.
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