March 18th, 2017, 12:36 AM  #1 
Newbie Joined: Mar 2017 From: Auckland Posts: 3 Thanks: 0 Math Focus: linear algebra  Jordan blocks
Hi all How do I demonstrate that a 3x3 Jordan block with diagonal values equal to β equals: β^n nβ^(n1) 0.5n(n1)β^(n2) 0 β^n nβ^(n1) 0 0 β^n For n=1,2,3 and so on? (and sorry for the poor notation, I can't work out how to write it more clearly). Thanks in advance for your help. I've been going around in circles with this one. 
March 18th, 2017, 04:34 PM  #2 
Global Moderator Joined: May 2007 Posts: 6,444 Thanks: 565 
notation problem  use latex

March 18th, 2017, 06:46 PM  #3 
Newbie Joined: Mar 2017 From: Auckland Posts: 3 Thanks: 0 Math Focus: linear algebra 
Sorry, I'm still learning to use latex. Here is a photo of my problem though. Thank you!

March 18th, 2017, 11:16 PM  #4 
Newbie Joined: Mar 2017 From: Auckland Posts: 3 Thanks: 0 Math Focus: linear algebra 
I have substituted in the values n= 1, 2, and 3 and it the equation works. But I cant work out how to prove it for k and k+1 without just substituting them in directly. Perhaps this is right and I shouldn't try to overcomplicate it! Thanks! 

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blocks, jordan 
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