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March 18th, 2017, 01:36 AM   #1
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Jordan blocks

Hi all

How do I demonstrate that a 3x3 Jordan block with diagonal values equal to β equals:

β^n nβ^(n-1) 0.5n(n-1)β^(n-2)
0 β^n nβ^(n-1)
0 0 β^n

For n=1,2,3 and so on?

(and sorry for the poor notation, I can't work out how to write it more clearly).

Thanks in advance for your help. I've been going around in circles with this one.
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March 18th, 2017, 05:34 PM   #2
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notation problem - use latex
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March 18th, 2017, 07:46 PM   #3
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Sorry, I'm still learning to use latex. Here is a photo of my problem though. Thank you!
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File Type: jpg IMG_1980.jpg (87.2 KB, 3 views)
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March 19th, 2017, 12:16 AM   #4
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I have substituted in the values n= 1, 2, and 3 and it the equation works. But I cant work out how to prove it for k and k+1 without just substituting them in directly. Perhaps this is right and I shouldn't try to over-complicate it!
Thanks!
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