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 March 18th, 2017, 12:36 AM #1 Newbie   Joined: Mar 2017 From: Auckland Posts: 3 Thanks: 0 Math Focus: linear algebra Jordan blocks Hi all How do I demonstrate that a 3x3 Jordan block with diagonal values equal to β equals: β^n nβ^(n-1) 0.5n(n-1)β^(n-2) 0 β^n nβ^(n-1) 0 0 β^n For n=1,2,3 and so on? (and sorry for the poor notation, I can't work out how to write it more clearly). Thanks in advance for your help. I've been going around in circles with this one.
 March 18th, 2017, 04:34 PM #2 Global Moderator   Joined: May 2007 Posts: 6,703 Thanks: 669 notation problem - use latex
March 18th, 2017, 06:46 PM   #3
Newbie

Joined: Mar 2017
From: Auckland

Posts: 3
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Math Focus: linear algebra
Sorry, I'm still learning to use latex. Here is a photo of my problem though. Thank you!
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 March 18th, 2017, 11:16 PM #4 Newbie   Joined: Mar 2017 From: Auckland Posts: 3 Thanks: 0 Math Focus: linear algebra I have substituted in the values n= 1, 2, and 3 and it the equation works. But I cant work out how to prove it for k and k+1 without just substituting them in directly. Perhaps this is right and I shouldn't try to over-complicate it! Thanks!

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