My Math Forum Basis

 Linear Algebra Linear Algebra Math Forum

 March 3rd, 2017, 04:37 PM #1 Member   Joined: Nov 2016 From: Kansas Posts: 55 Thanks: 0 Basis I have 2 vectors v1 and v2 which are linearly independent. I need to find v3 and v4 such that they form the basis of R4. How do I do that?
 March 3rd, 2017, 04:39 PM #2 Member   Joined: Nov 2016 From: Kansas Posts: 55 Thanks: 0 v1=( 0 1 -1 1) and v2=(1 -1 2 1)
March 3rd, 2017, 05:35 PM   #3
Senior Member

Joined: Sep 2015
From: Southern California, USA

Posts: 1,488
Thanks: 749

Quote:
 Originally Posted by ZMD v1=( 0 1 -1 1) and v2=(1 -1 2 1)
find a basis for the Null space of your two vectors.

Gaussian reducing we get

$\begin{pmatrix}0 &1 &-1 &1 \\ 1 &-1 &2 &1 \end{pmatrix}$

$\begin{pmatrix}1 &-1 &2 &1 \\0 &1 &-1 &1 \end{pmatrix}$

$\begin{pmatrix}1 &0 &1 &2 \\0 &1 &-1 &1 \end{pmatrix}$

$\begin{pmatrix}1 &0 &1 &2 \\0 &1 &0 &3 \end{pmatrix}$

and we can see the Null space is spanned by

$\begin{pmatrix}1 &0 &-1 &-2\end{pmatrix}$

and

$\begin{pmatrix}0 &1 &0 &-3\end{pmatrix}$

these two vectors along with the original two span $R^4$

as a check you can test that the determinant is non-zero.

$\left | \begin{pmatrix}0 &1 &-1 &1 \\ 1 &-1 &2 &1 \\ 1 &0 &-1 &-2 \\ 0 &1 &0 &-3\end{pmatrix}\right| = 12$

 Tags basis

 Thread Tools Display Modes Linear Mode

 Similar Threads Thread Thread Starter Forum Replies Last Post king.oslo Linear Algebra 0 September 29th, 2014 12:20 PM 84grandmarquis Linear Algebra 1 December 3rd, 2013 09:18 AM 84grandmarquis Linear Algebra 2 December 2nd, 2013 09:11 AM PhizKid Linear Algebra 1 November 25th, 2013 07:56 AM fahad nasir Linear Algebra 3 December 17th, 2012 02:36 PM

 Contact - Home - Forums - Cryptocurrency Forum - Top