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 January 21st, 2017, 05:56 PM #1 Newbie   Joined: Jan 2017 From: Pakistan Posts: 4 Thanks: 0 How to solve this problem? Let L:R-->R be defined by L(u)=au+b where a and b are any real numbers. Find all values of a and b so that L is a linear transformation. "Absolute honesty isn't the most diplomatic, nor the safest form of communication with emotional beings" Last edited by skipjack; January 21st, 2017 at 07:57 PM.
 January 21st, 2017, 06:04 PM #2 Senior Member     Joined: Sep 2015 From: USA Posts: 2,549 Thanks: 1399 a linear transform $f(x)$ has the properties that $f(x+y) = f(x)+f(y)$ $f(\alpha x) = \alpha f(x),~\alpha \in \mathbb{R}$ apply these to $L(u)=a u + b$ to determine which $a,b$ make $L(u)$ linear Thanks from muneeb977
January 21st, 2017, 06:36 PM   #3
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Quote:
 Originally Posted by romsek a linear transform $f(x)$ has the properties that $f(x+y) = f(x)+f(y)$ $f(\alpha x) = \alpha f(x),~\alpha \in \mathbb{R}$ apply these to $L(u)=a u + b$ to determine which $a,b$ make $L(u)$ linear
$L(u+v) = a(u+v) + b = a u + a v + b$

$L(u)+L(v) = a u + a v + 2b$

so what must the value of $b$ be in order for $L$ to be linear?

when $b$ is set to this value the second property is trivial to prove.

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