January 8th, 2017, 12:00 PM  #1 
Member Joined: Nov 2016 From: Ireland Posts: 67 Thanks: 2  Bogged in logs
I'm fairly familiar with logs  or so I thought. There's something tripping me up here though. Perhaps its the algebra. Something... anyways $\displaystyle log_4 x  log_4 (x1) = 2 $ I've got it to $\displaystyle log_4 x/x1 = 2$ Think I'm messing something up after that. I've tried transferring the power across $\displaystyle 4^2$ and working at it like that. Keep coming back with 0.6...... or even 0.6.... when I substitute the answer back in. I'm a lil burned out at this stage think I'm messing up the algebra. 
January 8th, 2017, 12:08 PM  #2 
Math Team Joined: Jul 2011 From: Texas Posts: 2,623 Thanks: 1303 
First, note that $x > 1$ $\log_4\left(\dfrac{x}{x1}\right)=2$ $4^2 = \dfrac{x}{x1}$ $16(x1)=x$ $16x16=x$ $15x=16$ $x=\dfrac{16}{15} >1$ 
January 8th, 2017, 12:19 PM  #3 
Member Joined: Nov 2016 From: Ireland Posts: 67 Thanks: 2 
Dang couldn't see the wood for the trees. Why it always look so simple when you guys do it? It's like watching pro golf. Anybody fancy lending me their brain for a day? Give you a good price for it. Sigh... thanks again Skeeter 

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