December 26th, 2016, 02:54 PM  #1 
Member Joined: Dec 2016 From:  Posts: 62 Thanks: 10  Operators exercise
Given two hermitian operators $A$ and $B$, both with positive eigenvalues, show that: \begin{eqnarray} \text {Tr}AB\geq 0 \end{eqnarray} I have done this part of the exercise, but the second part says to show that accordingly then \begin{eqnarray} AB= 0 \end{eqnarray} Where does this follow from? I cannot get a prove of this, some help please! 
December 28th, 2016, 04:54 PM  #2 
Global Moderator Joined: May 2007 Posts: 6,497 Thanks: 580 
Something doesn't look right. If A and B are identity matrices, they satisfy the conditions, but the product is an identity matrix.

December 29th, 2016, 06:48 AM  #3 
Member Joined: Dec 2016 From:  Posts: 62 Thanks: 10 
yes I know, that is why it looks odd to me...


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