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November 28th, 2016, 11:51 AM   #1
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expanding E

(e^2x + e^x) (e^-2x + e^-x)

= 2 + e^x + e^-x

Why's the answer to this, not 3 ? It's seems to multiply out through the rest of the equation why not at the end?
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November 28th, 2016, 11:57 AM   #2
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Originally Posted by Kevineamon View Post
(e^2x + e^x) (e^-2x + e^-x)

= 2 + e^x + e^-x

Why's the answer to this, not 3 ? It's seems to multiply out through the rest of the equation why not at the end?
Are you saying $\displaystyle e^x + e^{-x} = 1$? You are adding, not multiplying.

-Dan
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November 28th, 2016, 12:16 PM   #3
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Ahhh well then maybe that's it...

I calculated it to e^0
which is 1.

How are you doing the super script btw?
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November 28th, 2016, 12:33 PM   #4
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How are you doing the super script btw?
LaTex Help - My Math Forum
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November 28th, 2016, 01:54 PM   #5
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$\displaystyle e^x + e^{-x} = 1$
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November 28th, 2016, 01:56 PM   #6
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I see display style ...

Does it appear correctly to you guys?
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November 28th, 2016, 02:07 PM   #7
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oh never mind refreshed it and it appeared correctly
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