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November 27th, 2016, 10:57 AM  #1 
Newbie Joined: Nov 2016 From: Israel Posts: 4 Thanks: 0  How do I find the determinant of this matrix?
I have the following matrix: A  square matrix of n*n as follows: I figured out that the determinant is $\displaystyle (1)^n(n1)$, but how do I prove it? 
November 27th, 2016, 01:59 PM  #2 
Global Moderator Joined: May 2007 Posts: 6,276 Thanks: 516 
The matrix isn't here.

November 27th, 2016, 09:11 PM  #3 
Newbie Joined: Nov 2016 From: Israel Posts: 4 Thanks: 0 
Sorry, bad upload. This the matrix: 
November 27th, 2016, 10:02 PM  #4 
Senior Member Joined: Sep 2015 From: CA Posts: 1,300 Thanks: 664 
given an $n \times n$ matrix the determinant appears to be $(1)^{n1} (n1)$ now prove it using induction 
November 27th, 2016, 10:47 PM  #5 
Newbie Joined: Nov 2016 From: Israel Posts: 4 Thanks: 0 
I already know what the determinant is, I wrote it in the original post. What I don't know is how to prove it. I tried using induction ans it didn't work. Any other suggestions? 
November 28th, 2016, 03:20 AM  #6 
Newbie Joined: Nov 2016 From: United Kingdom Posts: 1 Thanks: 0 
Okay i know this is irrelevant and it might sound stupid but this question is driving me crazy, If x=4 and y=−5 find y2(xy+18 ) can someone please help me and show me how to answer the question, thanks! 
November 28th, 2016, 05:23 AM  #7 
Newbie Joined: Nov 2016 From: Israel Posts: 4 Thanks: 0  I don't understand how that has any connection to my question...


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determinant, find, matrix, proof 
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