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 November 27th, 2016, 10:57 AM #1 Newbie   Joined: Nov 2016 From: Israel Posts: 4 Thanks: 0 How do I find the determinant of this matrix? I have the following matrix: A - square matrix of n*n as follows: I figured out that the determinant is $\displaystyle (-1)^n(n-1)$, but how do I prove it?
 November 27th, 2016, 01:59 PM #2 Global Moderator   Joined: May 2007 Posts: 6,768 Thanks: 698 The matrix isn't here.
 November 27th, 2016, 09:11 PM #3 Newbie   Joined: Nov 2016 From: Israel Posts: 4 Thanks: 0 Sorry, bad upload. This the matrix:
 November 27th, 2016, 10:02 PM #4 Senior Member     Joined: Sep 2015 From: USA Posts: 2,463 Thanks: 1340 given an $n \times n$ matrix the determinant appears to be $(-1)^{n-1} (n-1)$ now prove it using induction
 November 27th, 2016, 10:47 PM #5 Newbie   Joined: Nov 2016 From: Israel Posts: 4 Thanks: 0 I already know what the determinant is, I wrote it in the original post. What I don't know is how to prove it. I tried using induction ans it didn't work. Any other suggestions?
 November 28th, 2016, 03:20 AM #6 Newbie   Joined: Nov 2016 From: United Kingdom Posts: 1 Thanks: 0 Okay i know this is irrelevant and it might sound stupid but this question is driving me crazy, If x=4 and y=−5 find y2(xy+18 ) can someone please help me and show me how to answer the question, thanks!
November 28th, 2016, 05:23 AM   #7
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Quote:
 Originally Posted by Mathmonsters Okay i know this is irrelevant and it might sound stupid but this question is driving me crazy, If x=4 and y=−5 find y2(xy+18 ) can someone please help me and show me how to answer the question, thanks!
I don't understand how that has any connection to my question...

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