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September 16th, 2016, 05:51 PM  #11 
Newbie Joined: Sep 2016 From: CO Posts: 6 Thanks: 0 
So I found some one else to help me. For reference the pattern is: $\displaystyle \sqrt[2^k]{n^{2^{k}1}}T(\sqrt[2^k]{n})+kn$ I have another question about recurrence relations. Which sub forum is the best to post about algorithms/discrete? 
September 16th, 2016, 07:26 PM  #12 
Global Moderator Joined: Oct 2008 From: London, Ontario, Canada  The Forest City Posts: 7,912 Thanks: 1110 Math Focus: Elementary mathematics and beyond 
Hi Hydro. That might very well be Computer Science. There's really no other forum that covers that sort of thing. I can move this thread there if you like.

October 3rd, 2016, 07:33 AM  #13 
Member Joined: Jan 2016 From: United States Posts: 61 Thanks: 7 
If that link is all you have to work with on the subject you might want to try some other material to get the hang of it." Rosen Discrete mathematics and it's applications" is a free pdf online and it provides a lot of examples and many practice exercises in chapter 8. it's a pretty gentle introduction to that kind of stuff, and if you get the hang of it and really like it, you could give knuth's book a shot.


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recurrence, relation, repeated, solve, subsitution 
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