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September 13th, 2016, 05:52 PM   #1
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linear equation with a constraint x>=35

Hi,

Does anyone have any advice on how to plot x>=35 (or any number) on a ti-83 plus? If I'm trying to solve a linear programming problem, such as maximizing 5x+6y with various constraints, I don't know how to ensure I get the correct answer if one of the constraints if x>= anything other than zero. This has happened often now where it will be x>=35 and it intersects at a point where I feel like I have to guess. I'd like to use a graphing calculator to ensure I'm getting the right answer but I don't see how anyone does this if you can't do anything on the x-axis.

An example of what I mean is found here where the person graphs the constraints on desmos.com where it accepts x=45. But if I'm taking a test how am I supposed to do this on a graphing calculator?
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September 13th, 2016, 07:22 PM   #2
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1. enter the functions as shown in the first screenshot

2. set a viewable window

3. graph the functions. hit the trace button, then type 45. the point (45,75) will display at the bottom of the screen.

4. hit the down arrow button, type in 45 again ... the point (45,60) will display at the bottom of the screen.
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File Type: png opt2.png (1.4 KB, 10 views)
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September 14th, 2016, 08:13 AM   #3
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Thanks!
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constraint, equation, linear, x&gt35, x>35



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