My Math Forum Coordinate conversion
 User Name Remember Me? Password

 Linear Algebra Linear Algebra Math Forum

 May 14th, 2010, 12:11 PM #1 Newbie   Joined: May 2010 Posts: 2 Thanks: 0 Coordinate conversion Being new here, I wasn't sure where to post this, especially because I don't know what area of math the answer will lay in. Anyway, I am a 3D computer graphics designer with a programming problem that needs a mathematical solution. Basically, the problem I have is that I have a 2D planar object that is mapped in one coordinate system and needs to be converted to another. The exact numbers that are being dealt with can vary, because the shape will vary, but the new coordinate system is always the same. The new system can only have values between 0 and one. I will be dealing with the coordinates as (x,z) points, so that means that the target planar map will have x values from 0 to 1 and z values from 0 to 1. What I am doing is looping through all existing vertices, finding the min and max values of x and z. Then I subtract the min from the max to see if x or z contains the largest span of numbers. Here's a bit of code that should be simple enough to understand if you are at all familiar with simple programming languages. Code: // nNumVertices contains the total number of x/z points we are dealing with //aAllVerts is an array containing all x/z pairs var minVertX = 0; var minVertZ = 0; var maxVertX = 0; var maxVertZ = 0; // Find max and min x and z values for( j = 0; j < nNumVertices; j++ ) { if ( aVertices[1] < minVertX) { minVertX = aVertices[1]; } if ( aVertices[1] > maxVertX) { maxVertX = aVertices[1]; } if ( aVertices[2] < minVertZ) { minVertZ = aVertices[2]; } if ( aVertices[2] > maxVertZ) { maxVertZ = aVertices[2]; } } // Determine if the x or z direction contains the greatest span of values if( maxVertX - minVertX > maxVertZ - minVertZ) { maxVertValue = maxVertX - minVertX; } if( maxVertValue < maxVertZ - minVertZ) { maxVertValue = maxVertZ - minVertZ; } The vertices that are to be converted can have both negative and positive values. For example: (x,Z) Vartices to be converted: 203.58326721191406 / 133.94407653808594 646.3115234375 / 912.4210815429688 -901.4326171875 / 1094.460205078125 -1500.000244140625 / 1735.3692626953125 -1500 / 133.94407653808594 In this illustration, the black values are the current x/z values, the blue values are what I want to convert to. Thanks, Beth
 May 18th, 2010, 06:57 AM #2 Newbie   Joined: Apr 2009 Posts: 19 Thanks: 0 Re: Coordinate conversion It seems to me that you're looking for the following: transform(x,y) = ((x-minVertX)/maxVertValue, (y-minVertY)/maxVertValue)
May 18th, 2010, 10:27 AM   #3
Newbie

Joined: May 2010

Posts: 2
Thanks: 0

Re: Coordinate conversion

Quote:
 Originally Posted by hkoehler transform(x,y) = ((x-minVertX)/maxVertValue, (y-minVertY)/maxVertValue)
That's it all right. As long as maxVertValue is the largest of all the vertex values, whether it's x or y.
In the example, maxVertValue = 1735.3692626953125.

I actually figured it out yesterday. But thanks for responding.

 Tags conversion, coordinate

 Thread Tools Display Modes Linear Mode

 Similar Threads Thread Thread Starter Forum Replies Last Post AJITnayak Calculus 2 December 30th, 2013 08:21 PM tancm Algebra 0 November 1st, 2012 05:07 AM Denegen Physics 0 May 22nd, 2012 10:57 PM swm06 Algebra 2 April 13th, 2012 10:34 AM Lpitt56 Algebra 5 February 29th, 2012 07:28 AM

 Contact - Home - Forums - Cryptocurrency Forum - Top