December 29th, 2009, 03:51 AM  #1 
Newbie Joined: Nov 2009 Posts: 15 Thanks: 0  Adjoint matrix
I need to prove that for a square matrix (nXn) A: if rkA= n1 then rk adjA= 1. Thanks for any help... 
January 29th, 2010, 07:31 AM  #2 
Newbie Joined: Jan 2010 Posts: 8 Thanks: 0  Re: Adjoint matrix
I don't know if this helps, but I looked up the Adjoint matrix on Wikipedia, and found this: http://en.wikipedia.org/wiki/Adjoint_matrix So, the adjoint matrix is the conjugate transpose, right? Well then, take the matrix: (1 0 0) (0 1 0) (0 0 0) The rank of this matrix is 2, which is n  1. It happens to be selfadjoint, so the rank of the adjoint is also 2, i.e. not 1. I don't think that it's true. 

Tags 
adjoint, matrix 
Thread Tools  
Display Modes  

Similar Threads  
Thread  Thread Starter  Forum  Replies  Last Post 
The matrix and it's adjoint will commute?  Zohaib  Linear Algebra  1  November 10th, 2011 06:23 AM 
Adjoint problem  typhoonss821  Linear Algebra  1  February 6th, 2010 06:11 AM 
Rank of Adjoint  BSActress  Linear Algebra  0  December 14th, 2009 07:33 AM 
Nonselfadjoint theory  Kungsman  Real Analysis  0  March 3rd, 2008 11:22 AM 
Finding the Adjoint Matrix and Wronskian  bjalongi  Linear Algebra  0  February 12th, 2008 08:47 PM 