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 July 11th, 2015, 02:29 PM #1 Newbie   Joined: Jul 2015 From: United States Posts: 14 Thanks: 0 Another Pythagorean Theorem question Use the Pythagorean Theorem to fine what b equals. I'm confused about the square root, I know the square root of something squared is just the number, but what about when there's a number and then the square root. Please help. Thanks in advance.
 July 11th, 2015, 02:47 PM #2 Math Team   Joined: Nov 2014 From: Australia Posts: 689 Thanks: 244 $(a\sqrt{b})^2 = a^2\cdot\sqrt{b}^2 = a^2b$
July 11th, 2015, 03:00 PM   #3
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Quote:
 Originally Posted by Azzajazz $(a\sqrt{b})^2 = a^2\cdot\sqrt{b}^2 = a^2b$
So in this case it would be 4^2*square root of 3 squared, which would equal 16*3, which equals 48.

Just wanted to be sure I did this right and got the point.

 July 11th, 2015, 04:03 PM #4 Math Team   Joined: Nov 2014 From: Australia Posts: 689 Thanks: 244 Correct! Well done. Thanks from littleredstar
July 11th, 2015, 06:11 PM   #5
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Quote:
 Originally Posted by Azzajazz $(a\sqrt{b})^2 = a^2\cdot\sqrt{b}^2 = a^2b$
Thank you so much! Also, how did you write the square roots and numbers the way you did??

July 12th, 2015, 07:25 PM   #6
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Quote:
 Originally Posted by littleredstar Thank you so much! Also, how did you write the square roots and numbers the way you did??
You quoted him, right? When you were typing containing his quote, you should be able to see the Latex code he used.

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