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July 11th, 2015, 02:29 PM   #1
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Post Another Pythagorean Theorem question



Use the Pythagorean Theorem to fine what b equals.

I'm confused about the square root, I know the square root of something squared is just the number, but what about when there's a number and then the square root. Please help.

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July 11th, 2015, 02:47 PM   #2
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$(a\sqrt{b})^2 = a^2\cdot\sqrt{b}^2 = a^2b$
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July 11th, 2015, 03:00 PM   #3
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Originally Posted by Azzajazz View Post
$(a\sqrt{b})^2 = a^2\cdot\sqrt{b}^2 = a^2b$
So in this case it would be 4^2*square root of 3 squared, which would equal 16*3, which equals 48.

Just wanted to be sure I did this right and got the point.
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July 11th, 2015, 04:03 PM   #4
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Correct! Well done.
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July 11th, 2015, 06:11 PM   #5
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Quote:
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$(a\sqrt{b})^2 = a^2\cdot\sqrt{b}^2 = a^2b$
Thank you so much! Also, how did you write the square roots and numbers the way you did??
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July 12th, 2015, 07:25 PM   #6
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Thank you so much! Also, how did you write the square roots and numbers the way you did??
You quoted him, right? When you were typing containing his quote, you should be able to see the Latex code he used.
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