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 July 1st, 2015, 07:33 PM #1 Newbie   Joined: Jul 2015 From: US Posts: 2 Thanks: 0 Parallel line calculations??? I have a set of lines where I know the beginning and end coordinates (X1, Y1, X2, Y2). What I need to calculate is a set of begin/end coordinates for parallel lines that makes the line a set distance away. Example, if I have coordinates (0,0,50,0), which is a horizontal line, and the distance required is 10, then what I should end up with is (0,10,50,10) a line that is parallel to the first but offset by 10. I plan to put in +10 and -10 for the distances to get lines the same distance on either side. How would I go about that? July 2nd, 2015, 04:13 AM #2 Math Team   Joined: Jan 2015 From: Alabama Posts: 3,264 Thanks: 902 For non-horizontal and non-vertical lines, the calculation is quite a lot more tedious. Suppose you have a line with one point $\displaystyle (x_0, y_0)$ and another point [math](x_1 , y_1)[math] (I would not say "end points"- lines do not have ends). You need to find a line perpendicular to that line at each point. The given line has slope $\displaystyle \frac{y_1- y_0}{x_1- x_0}$. Any line perpendicular to that given line must have slope $\displaystyle \frac{x_0- x_1}{y_1- y_0}$. A line through $\displaystyle (x_0, y_0)$ perpendicular to that given line has equation $\displaystyle y= \left(\frac{x_0- x_1}{y_1- y_0}\right)(x- x_0)+ y_0$. Now you will have to use the distance formula to find a point on this new line at the desired distance from $\displaystyle (x_0, y_0)$. Do the same with point $\displaystyle (x_1, y_1)$. Tags calculations, line, parallel Thread Tools Show Printable Version Email this Page Display Modes Linear Mode Switch to Hybrid Mode Switch to Threaded Mode Similar Threads Thread Thread Starter Forum Replies Last Post jaredbeach Calculus 4 May 12th, 2017 09:47 AM Limittox Geometry 2 April 12th, 2015 03:01 PM jmorris Pre-Calculus 4 November 19th, 2014 05:54 PM tx3 Algebra 4 May 23rd, 2013 11:47 PM fran1942 Calculus 5 April 2nd, 2012 08:48 PM

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