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April 16th, 2015, 12:56 AM  #1 
Newbie Joined: Apr 2015 From: Southampton Posts: 4 Thanks: 0  Help with circle sandwiched between two squares
I'm having real problems with this one. Can anyone help? Thanks in advance! See attached 
April 16th, 2015, 02:41 AM  #2 
Global Moderator Joined: Dec 2006 Posts: 20,624 Thanks: 2077 
By Pythagoras, AB² = 2AO² = 50cm². Hence AB = 5√2cm, and so the length of the perimeter of ABCD is 20√2cm. The corresponding length for square PQRS is 40cm. The circumference of the circle is 2$\pi$ × 5cm = 10$\pi$cm. Can you make progress from there? 

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circle, sandwiched, squares 
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