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April 16th, 2015, 12:56 AM   #1
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Help with circle sandwiched between two squares

I'm having real problems with this one. Can anyone help? Thanks in advance!

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April 16th, 2015, 02:41 AM   #2
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By Pythagoras, AB² = 2AO² = 50cm². Hence AB = 5√2cm, and so the length of the perimeter of ABCD is 20√2cm. The corresponding length for square PQRS is 40cm.

The circumference of the circle is 2$\pi$ × 5cm = 10$\pi$cm.

Can you make progress from there?
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