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January 31st, 2015, 04:20 AM   #1
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Plotting

How do I begin to sketch the polar curve of $\displaystyle r=2θ $
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January 31st, 2015, 04:30 AM   #2
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Mark some points and join them up with curves.

You will notice that the radius of the spiral increases by a fixed amount each revolution.
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January 31st, 2015, 06:56 AM   #3
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Yep it came good.

Now if I had to sketch the polar curve of $\displaystyle θ=-\frac{π}{3} $

Assuming θ is positive, I know that would be equal to the graph of $\displaystyle y=(√ 3)(x) $

But since θ is equal to a negative number how does that affect my graph?
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January 31st, 2015, 07:28 AM   #4
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$\displaystyle \theta = -\frac{\pi}{3}$

$\displaystyle \tan{\theta} = \tan\left(-\frac{\pi}{3}\right)$

$\displaystyle \tan{\theta} = -\sqrt{3}$

$\displaystyle \frac{y}{x} = -\sqrt{3}$

$\displaystyle y = -\sqrt{3} \cdot x$
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January 31st, 2015, 07:38 AM   #5
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So its sort of inverted, Thanks
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