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 January 31st, 2015, 04:20 AM #1 Senior Member     Joined: Dec 2014 From: Canada Posts: 110 Thanks: 4 Plotting How do I begin to sketch the polar curve of $\displaystyle r=2θ$
 January 31st, 2015, 04:30 AM #2 Math Team   Joined: Dec 2013 From: Colombia Posts: 7,660 Thanks: 2635 Math Focus: Mainly analysis and algebra Mark some points and join them up with curves. You will notice that the radius of the spiral increases by a fixed amount each revolution. Thanks from BonaviaFx
 January 31st, 2015, 06:56 AM #3 Senior Member     Joined: Dec 2014 From: Canada Posts: 110 Thanks: 4 Yep it came good. Now if I had to sketch the polar curve of $\displaystyle θ=-\frac{π}{3}$ Assuming θ is positive, I know that would be equal to the graph of $\displaystyle y=(√ 3)(x)$ But since θ is equal to a negative number how does that affect my graph?
 January 31st, 2015, 07:28 AM #4 Math Team     Joined: Jul 2011 From: Texas Posts: 2,924 Thanks: 1521 $\displaystyle \theta = -\frac{\pi}{3}$ $\displaystyle \tan{\theta} = \tan\left(-\frac{\pi}{3}\right)$ $\displaystyle \tan{\theta} = -\sqrt{3}$ $\displaystyle \frac{y}{x} = -\sqrt{3}$ $\displaystyle y = -\sqrt{3} \cdot x$ Thanks from BonaviaFx
 January 31st, 2015, 07:38 AM #5 Senior Member     Joined: Dec 2014 From: Canada Posts: 110 Thanks: 4 So its sort of inverted, Thanks

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