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 January 31st, 2015, 04:20 AM #1 Senior Member   Joined: Dec 2014 From: Canada Posts: 110 Thanks: 4 Plotting How do I begin to sketch the polar curve of $\displaystyle r=2θ$ January 31st, 2015, 04:30 AM #2 Math Team   Joined: Dec 2013 From: Colombia Posts: 7,660 Thanks: 2635 Math Focus: Mainly analysis and algebra Mark some points and join them up with curves. You will notice that the radius of the spiral increases by a fixed amount each revolution. Thanks from BonaviaFx January 31st, 2015, 06:56 AM #3 Senior Member   Joined: Dec 2014 From: Canada Posts: 110 Thanks: 4 Yep it came good. Now if I had to sketch the polar curve of $\displaystyle θ=-\frac{π}{3}$ Assuming θ is positive, I know that would be equal to the graph of $\displaystyle y=(√ 3)(x)$ But since θ is equal to a negative number how does that affect my graph? January 31st, 2015, 07:28 AM #4 Math Team   Joined: Jul 2011 From: Texas Posts: 2,924 Thanks: 1521 $\displaystyle \theta = -\frac{\pi}{3}$ $\displaystyle \tan{\theta} = \tan\left(-\frac{\pi}{3}\right)$ $\displaystyle \tan{\theta} = -\sqrt{3}$ $\displaystyle \frac{y}{x} = -\sqrt{3}$ $\displaystyle y = -\sqrt{3} \cdot x$ Thanks from BonaviaFx January 31st, 2015, 07:38 AM #5 Senior Member   Joined: Dec 2014 From: Canada Posts: 110 Thanks: 4 So its sort of inverted, Thanks  Tags plotting Thread Tools Show Printable Version Email this Page Display Modes Linear Mode Switch to Hybrid Mode Switch to Threaded Mode Similar Threads Thread Thread Starter Forum Replies Last Post Pumaftw Elementary Math 3 January 30th, 2015 04:31 AM uperkurk Elementary Math 1 January 25th, 2012 02:55 PM mathsissmart Computer Science 2 August 26th, 2011 09:55 AM wulfgarpro Algebra 1 May 5th, 2010 05:28 AM TranzRail New Users 6 October 8th, 2009 06:43 PM

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