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July 6th, 2014, 02:55 AM   #1
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the figure

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July 6th, 2014, 03:16 AM   #2
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$\displaystyle \dfrac{20}{\sin C}=\dfrac{10}{\sin 25}$ gives you

$\displaystyle C=\sin^{-1}(2 \sin 25)$ and $\displaystyle ADB=180-C$.

Saying $\displaystyle m\angle ADB > m \angle C$ is useless since it is always true.
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