July 6th, 2014, 02:55 AM  #1 
Senior Member Joined: Nov 2013 Posts: 434 Thanks: 8  the figure 
July 6th, 2014, 03:16 AM  #2 
Senior Member Joined: Feb 2010 Posts: 711 Thanks: 147 
$\displaystyle \dfrac{20}{\sin C}=\dfrac{10}{\sin 25}$ gives you $\displaystyle C=\sin^{1}(2 \sin 25)$ and $\displaystyle ADB=180C$. Saying $\displaystyle m\angle ADB > m \angle C$ is useless since it is always true. 

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