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 April 1st, 2019, 03:02 PM #1 Senior Member   Joined: Mar 2019 From: TTF area Posts: 177 Thanks: 1 A geometry time question If a rescue craft is launched from Miami and can travel with a maximum speed of 35 knots, how long should it take to reach the crash site? Note: 1 knot = 1.852 km/hr. The approximate distance in this region for latitude of 1° = 111 km and longitude 1° = 100 km. Let's suppose the coordinates is (-71,25) Miami is (−80,26). Have I solved it?? 13hrs 59m 33s??? Last edited by skipjack; April 1st, 2019 at 06:16 PM.
 April 1st, 2019, 03:15 PM #2 Math Team     Joined: Jul 2011 From: Texas Posts: 3,092 Thanks: 1674 assuming your coordinates are (longitude,latitude), I get about 10 second less time. Thanks from helpmeddddd
 April 1st, 2019, 03:25 PM #3 Senior Member   Joined: Mar 2019 From: TTF area Posts: 177 Thanks: 1 Yeah they are longitude, latitude. What process did you use to solve I'm interested! if you could please reply thanks. I personally multiplied both longitude coordinates by 100 and the latitude by 111, getting -80x100, -71x100, 25x111, 26x111, then I put them into the square root (x2-x1)squared + (y2-y1)squared to get 907km, then I used the time = d/s to get my answer. Last edited by skipjack; April 2nd, 2019 at 02:03 PM.
 April 1st, 2019, 03:45 PM #4 Math Team     Joined: Jul 2011 From: Texas Posts: 3,092 Thanks: 1674 $t = \dfrac{\sqrt{900^2 + 111^2}}{35 \cdot 1.852} = 13.989... \, hrs$ $(0.989... \, hrs)(60 \, min/hr) = 59.388... \, min$ $(0.388... \, min)(60 \, sec/min) \approx 23.3 \, sec$ 13 hrs 59 min 23 sec
 April 1st, 2019, 03:47 PM #5 Senior Member   Joined: Mar 2019 From: TTF area Posts: 177 Thanks: 1 maybe my calculations are wrong ?? Last edited by helpmeddddd; April 1st, 2019 at 03:51 PM.
April 1st, 2019, 03:51 PM   #6
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Quote:
 Originally Posted by helpmeddddd I see you are multiplying by knots (35) whereas I'm multiplying by 64.82km/hr
1 kt = 1.852 km/hr $\implies$ 35 kts = 35(1.852) km/hr = 64.82 km/hr

same same

 April 1st, 2019, 03:54 PM #7 Senior Member   Joined: Mar 2019 From: TTF area Posts: 177 Thanks: 1 Yeah you are right is there any mathematical statement I can use to go alongside this?
April 1st, 2019, 03:58 PM   #8
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Quote:
 Originally Posted by helpmeddddd Yeah you are right is there any mathematical statement I can use to go alongside this?
what do you mean? it's just a problem involving $time = \dfrac{distance}{speed}$ with a couple of unit conversions

 April 1st, 2019, 04:05 PM #9 Senior Member   Joined: Mar 2019 From: TTF area Posts: 177 Thanks: 1 Yeah, I don't know. Could you be please check I've correctly solved my other problem on another thread. I'll just put it in this box. question A plane's emergency beacon goes off, its approx position is at a place equidistant from Miami and San Juan and on altitude from Miami, in the Bermuda triangle. Locate where the plane has crashed M(−80,26), H(−65,32), S(−66,18). Last edited by skipjack; April 1st, 2019 at 06:02 PM.
April 1st, 2019, 04:31 PM   #10
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Quote:
 Originally Posted by helpmeddddd Yeah, I don't know. Could you be please check I've correctly solved my other problem on another thread. I'll just put it in this box. question A plane's emergency beacon goes off, its approx position is at a place equidistant from Miami and San Juan and on altitude from Miami, in the Bermuda triangle. Locate where the plane has crashed M(−80,26), H(−65,32), S(−66,18).
M is probably Miami, S is probably San Juan ... what does H represent?

Last edited by skipjack; April 1st, 2019 at 06:03 PM.

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