Geometry Geometry Math Forum

 September 13th, 2018, 07:33 PM #1 Newbie   Joined: Aug 2018 From: United States Posts: 2 Thanks: 0 geometric transformations Matt wants to reflect a shape over the x-axis and then reflect it over the y-axis. Cathy says that this would be the same as rotating the shape 180 degrees. Do you agree or disagree with Cathy? Justify your answer and use matrix transformations as part of your justification. thanks for any help!! September 13th, 2018, 07:54 PM #2 Senior Member   Joined: Sep 2015 From: USA Posts: 2,647 Thanks: 1476 suppose we have a point $(x,y)$ Reflecting it would be accomplished by pre-multiplying by the matrix $ref_x = \begin{pmatrix}-1 &0 \\ 0 &1\end{pmatrix}$ similarly $ref_y = \begin{pmatrix}1 &0 \\ 0 &-1\end{pmatrix}$ multiplying these two reflections matrices $ref_y ref_x = \begin{pmatrix}-1 &0 \\ 0 &-1 \end{pmatrix}$ a rotation matrix of $\pi$ radians is given by $rot_\pi = \begin{pmatrix}\cos(\pi) &\sin(\pi) \\ -\sin(\pi) &\cos(\pi) \end{pmatrix} =\begin{pmatrix}-1 &0 \\ 0 &-1 \end{pmatrix}$ and we see that the two reflections are indeed equivalent to the single rotation by $\pi$ September 13th, 2018, 09:17 PM #3 Global Moderator   Joined: Dec 2006 Posts: 21,124 Thanks: 2332 Your $ref_x$, $ref_y$ and $rot$ are usually denoted by $\operatorname{Ref_y}$, $\operatorname{Ref_x}$ and $\operatorname{Rot}$ respectively. If the point $(x,~ y)$ is written as a row vector, use post-multiplication. If the point $(x,~ y)$ is written as a column vector, use pre-multiplication. Tags geometric, transformations Thread Tools Show Printable Version Email this Page Display Modes Linear Mode Switch to Hybrid Mode Switch to Threaded Mode Similar Threads Thread Thread Starter Forum Replies Last Post u17159BR Trigonometry 2 May 31st, 2018 05:19 PM laxus95 Linear Algebra 2 December 11th, 2013 06:40 PM reto11 Applied Math 1 October 18th, 2010 11:08 PM Adrian Algebra 10 July 7th, 2010 05:40 PM math8553 Linear Algebra 1 December 2nd, 2008 06:34 PM

 Contact - Home - Forums - Cryptocurrency Forum - Top      