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 September 3rd, 2018, 11:03 PM #1 Member   Joined: Aug 2018 From: Nigeria Posts: 73 Thanks: 2 Analytical Geometry The perpendicular bisector of the line AB is 3y - 2x - 4 = 0. If A is the point (6,5), find B's coordinates. Last edited by skipjack; September 4th, 2018 at 03:55 AM.
 September 4th, 2018, 12:01 AM #2 Senior Member     Joined: Jul 2010 From: St. Augustine, FL., U.S.A.'s oldest city Posts: 12,211 Thanks: 521 Math Focus: Calculus/ODEs What is the slope of the line: $\displaystyle 3y-2x-4=0$
 September 4th, 2018, 12:54 AM #3 Member   Joined: Aug 2018 From: Nigeria Posts: 73 Thanks: 2 m=2/3
 September 4th, 2018, 04:15 AM #4 Global Moderator   Joined: Dec 2006 Posts: 21,034 Thanks: 2271 Correct. That implies that AB has slope -3/2. Hence AB has equation 2y + 3x = 2*5 + 3*6 = 28. The coordinates (x, y) = (76/13, 68/13) satisfy both equations, so they are the coordinates of the mid-point of AB. Can you now find the coordinates of B?
 September 4th, 2018, 06:07 AM #5 Member   Joined: Aug 2018 From: Nigeria Posts: 73 Thanks: 2 Yes. Since 2M-A=B

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