August 29th, 2018, 10:58 PM  #1 
Member Joined: Aug 2018 From: Nigeria Posts: 56 Thanks: 2  Geometry of coordinate
Find the perimeter of a rhombus PQRS with vertices P(2,3),Q(1,1),R(4,3)and S(1,7)

August 29th, 2018, 11:13 PM  #2 
Global Moderator Joined: Dec 2006 Posts: 19,977 Thanks: 1851 
PQRS isn't a rhombus. Are you sure those are the correct coordinates?

August 29th, 2018, 11:41 PM  #3 
Member Joined: Aug 2018 From: Nigeria Posts: 56 Thanks: 2 
Yes...100% Sure...Why did you say it is not correct?but please if it is not teach me how to solve similar question

August 29th, 2018, 11:55 PM  #4 
Member Joined: Aug 2018 From: Nigeria Posts: 56 Thanks: 2 
I need help solving similar question

August 30th, 2018, 12:35 AM  #5 
Math Team Joined: May 2013 From: The Astral plane Posts: 1,915 Thanks: 774 Math Focus: Wibbly wobbly timeywimey stuff. 
This is why skipjack was wondering. Dan 
August 30th, 2018, 12:38 AM  #6  
Math Team Joined: May 2013 From: The Astral plane Posts: 1,915 Thanks: 774 Math Focus: Wibbly wobbly timeywimey stuff.  Quote:
So one side of this is PQ. We have $\displaystyle \sqrt{ (2 1)^2 + (3  1)^2 } = \sqrt{13}$. Get the vertices of an actual rhombus and try it out. Dan  
August 30th, 2018, 12:40 AM  #7 
Global Moderator Joined: Dec 2006 Posts: 19,977 Thanks: 1851 
For a rhombus, each side has the same length.

August 30th, 2018, 03:09 AM  #8 
Member Joined: Aug 2018 From: Nigeria Posts: 56 Thanks: 2 
Oh....I get it,after my own research on using 'THE DISTANCE FORMULA'' i would end up to have length '5' and breadth'6' which is not the property of a rhombus but the property of a rectangle which leads me to P=4L therefore obtaining20..That means this is a mistake in my textbook 

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