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August 29th, 2018, 09:58 PM   #1
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Geometry of coordinate

Find the perimeter of a rhombus PQRS with vertices P(-2,3),Q(1,1),R(4,3)a-nd S(1,-7)
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August 29th, 2018, 10:13 PM   #2
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PQRS isn't a rhombus. Are you sure those are the correct coordinates?
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August 29th, 2018, 10:41 PM   #3
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Yes...100% Sure...Why did you say it is not correct?but please if it is not teach me how to solve similar question
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August 29th, 2018, 10:55 PM   #4
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I need help solving similar question
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August 29th, 2018, 11:35 PM   #5
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Math Focus: Wibbly wobbly timey-wimey stuff.
This is why skipjack was wondering.

-Dan
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August 29th, 2018, 11:38 PM   #6
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Math Focus: Wibbly wobbly timey-wimey stuff.
Quote:
Originally Posted by Harmeed View Post
Find the perimeter of a rhombus PQRS with vertices P(-2,3),Q(1,1),R(4,3)a-nd S(1,-7)
What you would do (if this were a real rhombus) is to use the distance formula between all neighboring points. (That is, not across a diagonal.)

So one side of this is PQ. We have $\displaystyle \sqrt{ (-2 -1)^2 + (3 - 1)^2 } = \sqrt{13}$.

Get the vertices of an actual rhombus and try it out.

-Dan
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August 29th, 2018, 11:40 PM   #7
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For a rhombus, each side has the same length.
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August 30th, 2018, 02:09 AM   #8
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Oh....I get it,after my own research on using 'THE DISTANCE FORMULA'' i would end up to have length '5' and breadth'6' which is not the property of a rhombus but the property of a rectangle which leads me to
P=4L therefore obtaining20..That means this is a mistake in my textbook
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