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 August 29th, 2018, 09:58 PM #1 Member   Joined: Aug 2018 From: Nigeria Posts: 43 Thanks: 2 Geometry of coordinate Find the perimeter of a rhombus PQRS with vertices P(-2,3),Q(1,1),R(4,3)a-nd S(1,-7)
 August 29th, 2018, 10:13 PM #2 Global Moderator   Joined: Dec 2006 Posts: 19,701 Thanks: 1804 PQRS isn't a rhombus. Are you sure those are the correct coordinates? Thanks from topsquark
 August 29th, 2018, 10:41 PM #3 Member   Joined: Aug 2018 From: Nigeria Posts: 43 Thanks: 2 Yes...100% Sure...Why did you say it is not correct?but please if it is not teach me how to solve similar question
 August 29th, 2018, 10:55 PM #4 Member   Joined: Aug 2018 From: Nigeria Posts: 43 Thanks: 2 I need help solving similar question
August 29th, 2018, 11:35 PM   #5
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This is why skipjack was wondering.

-Dan
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August 29th, 2018, 11:38 PM   #6
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Quote:
 Originally Posted by Harmeed Find the perimeter of a rhombus PQRS with vertices P(-2,3),Q(1,1),R(4,3)a-nd S(1,-7)
What you would do (if this were a real rhombus) is to use the distance formula between all neighboring points. (That is, not across a diagonal.)

So one side of this is PQ. We have $\displaystyle \sqrt{ (-2 -1)^2 + (3 - 1)^2 } = \sqrt{13}$.

Get the vertices of an actual rhombus and try it out.

-Dan

 August 29th, 2018, 11:40 PM #7 Global Moderator   Joined: Dec 2006 Posts: 19,701 Thanks: 1804 For a rhombus, each side has the same length.
 August 30th, 2018, 02:09 AM #8 Member   Joined: Aug 2018 From: Nigeria Posts: 43 Thanks: 2 Oh....I get it,after my own research on using 'THE DISTANCE FORMULA'' i would end up to have length '5' and breadth'6' which is not the property of a rhombus but the property of a rectangle which leads me to P=4L therefore obtaining20..That means this is a mistake in my textbook

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