User Name Remember Me? Password

 Geometry Geometry Math Forum

 August 22nd, 2018, 02:37 AM #1 Member   Joined: Aug 2018 From: Nigeria Posts: 73 Thanks: 2 Equation of a line Help!!! I need a mathematician to solve this... The line 5x+Ky-15=0 is perpendicular to the line 2x+5y-3=0,find the value of K. Last edited by Harmeed; August 22nd, 2018 at 02:40 AM. Reason: to erase August 22nd, 2018, 03:35 AM   #2
Senior Member

Joined: May 2016
From: USA

Posts: 1,310
Thanks: 552

Quote:
 Originally Posted by Harmeed Help!!! I need a mathematician to solve this... The line 5x+Ky-15=0 is perpendicular to the line 2x+5y-3=0,find the value of K.
A few questions.

The slope of line A has a slope of m. Line B is perpendicular to line A. What is the slope of line B? The answer to that question should be in your text or lecture notes, but you may not have seen its relevance.

Its relevance is this: if you determine the slope of 2x + 5y - 3 = 0, you can then find the slope of 5x + ky - 15 = 0. And then you can find k.

So what is the slope of 2x + 5y - 3 = 0? August 22nd, 2018, 08:02 AM #3 Member   Joined: Aug 2018 From: Nigeria Posts: 73 Thanks: 2 The slope of 5x+Ky-15=0 is -5/k and 2x+5y-3=0 is -2/5...Help me guy how are my going to find constant k Thanks from o2jam August 22nd, 2018, 08:12 AM #4 Senior Member   Joined: Sep 2015 From: USA Posts: 2,584 Thanks: 1430 the product of the slopes of two perpendicular lines is -1 August 24th, 2018, 03:53 PM   #5
Newbie

Joined: Aug 2018
From: PA

Posts: 2
Thanks: 0

Math Focus: geometry
Quote:
 Originally Posted by Harmeed The slope of 5x+Ky-15=0 is -5/k and 2x+5y-3=0 is -2/5...Help me guy how are my going to find constant k
the opposite reciprocal of -2/5x is 5/2x, so the first equation's slope has to equal this value, and the only way to do that is by letting k be 2 and then dividing 5x by 2 to get 5/2x once you first rewrite the equations in slope-intercept form. Please correct me if i'm wrong I would like to know the correct solution.  Tags equation, equations, line Thread Tools Show Printable Version Email this Page Display Modes Linear Mode Switch to Hybrid Mode Switch to Threaded Mode Similar Threads Thread Thread Starter Forum Replies Last Post cfern87 Calculus 0 October 27th, 2017 08:10 PM Matkenis Algebra 3 April 13th, 2017 07:09 AM amirus14 Algebra 9 January 21st, 2012 09:56 AM luketapis Algebra 1 November 23rd, 2011 03:19 PM amirus14 Calculus 1 December 31st, 1969 04:00 PM

 Contact - Home - Forums - Cryptocurrency Forum - Top      