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 Geometry Geometry Math Forum

July 3rd, 2018, 09:21 AM   #1
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Distance between chords

My attempt:
$\displaystyle \cos(\theta) =1/7=81.7.$
It is the same for both the angles. But how to find distance?
Attached Images Circle.jpg (11.9 KB, 4 views)

Last edited by skipjack; July 3rd, 2018 at 10:04 AM. July 3rd, 2018, 09:41 AM #2 Senior Member   Joined: Jul 2010 From: St. Augustine, FL., U.S.A.'s oldest city Posts: 12,211 Thanks: 521 Math Focus: Calculus/ODEs As: $\displaystyle \arccos(x)= \text{arcsec}\left(\frac{1}{x}\right)$ where $\displaystyle x\ne0$ We see the two chords subtend the same angle, and are therefore the same distance $\displaystyle d$ from the center. Thus, the distance between the two chords is: $\displaystyle 2d=4\cos\left(\frac{\arccos\left(\frac{1}{7}\right )}{2}\right)=\frac{8}{\sqrt{7}}$ Thanks from MathsLearner123 July 3rd, 2018, 10:26 AM   #3
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Quote:
 Originally Posted by MathsLearner123 $\displaystyle \cos(\theta) =1/7=81.7.$
$\theta = \cos^{-1}\frac17= 81.8^\circ\!$ approximately. Tags chords, distance Thread Tools Show Printable Version Email this Page Display Modes Linear Mode Switch to Hybrid Mode Switch to Threaded Mode Similar Threads Thread Thread Starter Forum Replies Last Post Leonardox Geometry 14 April 13th, 2017 11:53 PM bilano99 Algebra 3 May 20th, 2013 10:16 PM bilano99 Algebra 3 May 19th, 2013 07:49 AM Taraalcar Algebra 1 June 2nd, 2012 12:22 PM stevecowall Algebra 7 January 7th, 2012 07:26 AM

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