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June 14th, 2018, 02:06 AM   #1
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Maximum area of triangle

Sorry for lot of questions. But please help me to solve this problem
My Attempt:
Area = (1/2) * Base * Height;
Area = (1/2) * p*q;
Maximum is infinite value because p and q can take any value.
Am I correct? Please help. I think I am nowhere near the correct thinking.
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Last edited by skipjack; June 14th, 2018 at 02:23 AM.
MathsLearner123 is offline  
June 14th, 2018, 02:36 AM   #2
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Given the values of p and q, you might as well fix the position of the line segment AB, as doing so won't affect the required area. AB can be called the base of the triangle. The distance of C from AB can be called the height of the triangle. The area of the triangle is maximized when this distance is maximized, because the area is half the product of this distance and p, the length of the base. To maximize the distance of C from AB, BC must be perpendicular to AB, and the maximized distance is then q, the length of BC. The area of triangle ABC is then pq/2.
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June 14th, 2018, 03:12 PM   #3
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From the textbook History of Mathematical Thought (Kline, I believe), it actually hasnt been proven the sum of the angles of a triangle must always add up to 180 degrees. It had something to do with parallel lines not having to be exacty parallel before being provably non-intersecting. The sum of the angles of a triangle can be more than 180 degrees given the assumption. This from a class I took about 15 years ago so sorry not more specific. I assume the above would impact the area.

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June 14th, 2018, 04:30 PM   #4
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A far more interesting question is what is the maximum area of a triangle given some properties that limit it's area.

For example what is the maximum area of a triangle with perimeter P.

Or what is the maximum area given a triangle with two sides of length p and q.
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