April 8th, 2018, 06:11 AM  #1 
Senior Member Joined: Nov 2010 From: Indonesia Posts: 1,951 Thanks: 132 Math Focus: Trigonometry  [ASK] P to AC
Given an ABCD.EFGH cube whose its side length is 8 cm. The point P is within AB so that AP = 3PH. The distance between P to AC is .... A. $\displaystyle 2\sqrt3$ cm B. $\displaystyle 3\sqrt3$ cm C. $\displaystyle 2\sqrt6$ cm D. $\displaystyle 3\sqrt6$ cm E. $\displaystyle 4\sqrt6$ cm So AH is $\displaystyle 8\sqrt2$ cm and PH = $\displaystyle 6\sqrt2$. What do I do now? Is the triangle HPC a right triangle? 
April 8th, 2018, 06:45 AM  #2 
Global Moderator Joined: Dec 2006 Posts: 18,961 Thanks: 1605 
Something's incorrect in your description.

April 8th, 2018, 07:02 AM  #3 
Senior Member Joined: Nov 2010 From: Indonesia Posts: 1,951 Thanks: 132 Math Focus: Trigonometry 
Sorry, I mean $\displaystyle PH=2\sqrt2$ cm.
