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 April 8th, 2018, 07:11 AM #1 Senior Member     Joined: Nov 2010 From: Indonesia Posts: 2,001 Thanks: 132 Math Focus: Trigonometry [ASK] P to AC Given an ABCD.EFGH cube whose its side length is 8 cm. The point P is within AB so that AP = 3PH. The distance between P to AC is .... A. $\displaystyle 2\sqrt3$ cm B. $\displaystyle 3\sqrt3$ cm C. $\displaystyle 2\sqrt6$ cm D. $\displaystyle 3\sqrt6$ cm E. $\displaystyle 4\sqrt6$ cm So AH is $\displaystyle 8\sqrt2$ cm and PH = $\displaystyle 6\sqrt2$. What do I do now? Is the triangle HPC a right triangle?
 April 8th, 2018, 07:45 AM #2 Global Moderator   Joined: Dec 2006 Posts: 20,098 Thanks: 1905 Something's incorrect in your description.
 April 8th, 2018, 08:02 AM #3 Senior Member     Joined: Nov 2010 From: Indonesia Posts: 2,001 Thanks: 132 Math Focus: Trigonometry Sorry, I mean $\displaystyle PH=2\sqrt2$ cm.

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